Q: How do you put y equals c in a calculator?

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If you put this equation in y-intercept form it is y=4/3x+20 If you have a graphing calculator just enter this in "y=" or graph it manually to find the x-intercept.

y=5a-3b+c a=12b=4c=8 a=8 b=2/3 c=2 y=5(8)-3(2/3)+(4) y=40-2+4 y=38 y = 823

y varies directly as x so y = cx for some constant c. y = 125 when x = 25 so 125 = c*25 so that c = 5 ie the relationship is y = 5x Then when x = 2, y = c*x = 5*2 = 10

y = arcsin( cos 48 ); arcsin may be seen as sin-1 on your calculator.

The y-intercept of y=3x+1 is at the point (0,1)(i worked it out on a graphics calculator my apologies if you needed working out.)

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If you put this equation in y-intercept form it is y=4/3x+20 If you have a graphing calculator just enter this in "y=" or graph it manually to find the x-intercept.

x + y + z = 0 x = a - b, y = b - c, z = c - a, therefore a - b + b - c + c - a = ? a - a + b - b + c - c = 0

y=5a-3b+c a=12b=4c=8 a=8 b=2/3 c=2 y=5(8)-3(2/3)+(4) y=40-2+4 y=38 y = 823

just put x^2=y or (x^2)/y on the calculator, and then it makes a simple parabola.

well, m is the slope and c is the y-intercept

It is the intercept: the value that y takes when x = 0

y varies directly as x so y = cx for some constant c. y = 125 when x = 25 so 125 = c*25 so that c = 5 ie the relationship is y = 5x Then when x = 2, y = c*x = 5*2 = 10

y = arcsin( cos 48 ); arcsin may be seen as sin-1 on your calculator.

c

The y-intercept of y=3x+1 is at the point (0,1)(i worked it out on a graphics calculator my apologies if you needed working out.)

c is any constant value

y' = (sec(x))^2