change the y value to -y, and bring the negative over the equal sign. example. y=2x^2 reflected on the x-axis looks like y=(2x^2)/-1 which is equal to y=-(2x^2)
First you go over how many spaces then you go up how many spaces
u just make both the inverted version of them y is -y and 2 is -2
y=10/7
If you reflect a function across the line y=x, you will have a graph of the inverse. For trigonometric problems: y = sin(x) has the inverse x=sin(y) or y = sin-1(x)
You change the value of y to -y. ex: (4,5) reflected over the x-axis is (4,-5)
You switch the x and y coordinates of the line. In other words, (x,y) ---> (y,x). I hope this helps! :)
substitute x = y and y = -x Ex: y = x2 becomes -x = y2
(-2,3) reflected over y = x is (3,-2) (400,-2) reflected over y = x is (-2,400) All you do is switch the ordered pair.
To reflect a point in the x axis, multiply it's y coordinate by -1. Example: (x, y) over the x axis is now (x, -y), If you come across the y already being a negative, then make it a positive, (x, -y) = (x, y). The x stays the same, and vice versa over the y axis. Hope I helped. I am also having trouble with this, though, What if there is a zero? (5,0), it can't be (5, -0) can it?
change the y value to -y, and bring the negative over the equal sign. example. y=2x^2 reflected on the x-axis looks like y=(2x^2)/-1 which is equal to y=-(2x^2)
I dont really know if this is right but i think to do this problem you have to take a point then rotate the paper counter clockwise around the origin then you have a new point which is called a prime. Then reflect it over the y axis on the graph.
count the spaces on your graph until you reach the y axis then start over and count again till you count the same number that you it took you to reach the y axis... sounds kinda confusing.... but good luck !
If it is Rx=0, it means you are reflecting your set of coordinates and reflect it across the x-axis when x=0. So it pretty much is saying reflect it over the y-axi
First you go over how many spaces then you go up how many spaces
if you need to reflect a 2-d object on a graph over its parent linear function then do as follows: (x,y) --> (-y,-x) hope that helps
The bit with the negative x-axis goes to the positive x-axis.