'csc' = 1/sin
'tan' = sin/cos
So it must follow that
(cos) (csc) / (tan) = (cos) (1/sin)/(sin/cos) = (cos) (1/sin) (cos/sin) = (cos/sin)2
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For a start, try converting everything to sines and cosines.
The side adjacent to theta divided by the hypotenuse, or the angle opposite of the right angle
There can be no significant simplicfication if some of the angles are theta and others are x, so assume that all angles are x. [csc(x) - cot(x)]*[cos(x) + 1] =[1/sin(x) - cos(x)/sin(x)]*[cos(x) + 1] =1/sin(x)*[1 - cos(x)]*[cos(x) + 1] =1/sin(x)*[1 - cos2(x)] =1/sin(x)*[sin2(x)] = sin(x)
A - WORKWork = F.s cos (theta)
The identity for tan(theta) is sin(theta)/cos(theta).