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For a start, try converting everything to sines and cosines.

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โˆ™ 2011-04-25 12:22:12
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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

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A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: How do you simplify csc theta -cot theta cos theta?
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How do you make 'cot' and 'csc' on a TI-84 graphing calculator?

From math class, some trigonometric identities: cot x = 1/tan x csc x = 1/sin x sec x = 1/cos x There are no built-in cot or csc formulas, so use the above. Remember that these give errors when tan x, sin x, or cos x are equal to 0.


Any interesting way in teaching right angle trigonometry?

Below link may help.You need to memorize the basic formulas and it will be easy.pythagorean theoremc² = a² + b²Sine Theta (sin θ) = opposite/hypotenuse = a/cCosine Theta (cos θ) = adjacent/hypotenuse = b/cTangent Theta (tan θ) = opposite/adjacent = a/bCotangent Theta (cot θ) = adjacent/opposite = b/aSecant Theta (sec θ) = hypotenuse/adjacent = c/bCosecant Theta (csc θ) = hypotenuse/opposite = c/a


What is the derivative of 3tanx-4cscx?

7


Right Triangle Find all the missing sides and angles And the six trigonometric functions No 1 side a 6 side b 9 No 2 side a 21 side c 27 No 3 side b 2 square of 10 side c 7?

No.1 A right triangle with sides 6, 9 and 10.82 will have angles of 33.69 and 56.31 sin(33.69) = 0.554699 cos(33.69) = 0.832051 tan(33.69) = 0.666665 cot(33.69) = 1.500004 sec(33.69) = 1.201849 csc(33.69) = 1.802779 sin(56.31) = 0.832051 cos(56.31) = 0.554699 tan(56.31) = 1.500004 cot(56.31) = 0.666665 sec(56.31) = 1.802779 csc(56.31) = 1.201849 No.2 A right triangle with sides 16.97, 21 and 27 will have angles of 38.94 and 51.06 sin(38.94) = 0.628506 cos(38.94) = 0.777805 tan(38.94) = 0.808052 cot(38.94) = 1.237545 sec(38.94) = 1.28567 csc(38.94) = 1.591074 sin(51.06) = 0.777805 cos(51.06) = 0.628506 tan(51.06) = 1.237545 cot(51.06) = 0.808052 sec(51.06) = 1.591074 csc(51.06) = 1.28567 No. 3 A right triangle with sides 3, 6.32 and 7 will have angles of 25.38 and 64.62 sin(25.38) = 0.42862 cos(25.38) = 0.903485 tan(25.38) = 0.474407 cot(25.38) = 2.107894 sec(25.38) = 1.106825 csc(25.38) = 2.33307 sin(64.62) = 0.903485 cos(64.62) = 0.42862 tan(64.62) = 2.107894 cot(64.62) = 0.474407 sec(64.62) = 2.33307 csc(64.62) = 1.106825


What is the second derivative of ln(tan(x))?

f'(x) = 1/tan(x) * sec^2(x) where * means multiply and ^ means to the power of. = cot(x) * sec^2(x) f''(x) = f'(cot(x)*sec^2(x) + cot(x)*f'[sec^2(x)] = -csc^2(x)*sec^2(x) + cot(x)*2tan(x)sec^2(x) = sec^2(x) [cot(x)-csc^2(x)] +2tan(x)cot(x) = sec^2(x) [cot(x)-csc^2(x)] +2

Related questions

How do you simplify csc theta cot theta cos theta?

cosec(q)*cot(q)*cos(q) = 1/sin(q)*cot(q)*cos(q) = cot2(q)


How do you simplify cos theta times csc theta divided by tan theta?

'csc' = 1/sin'tan' = sin/cosSo it must follow that(cos) (csc) / (tan) = (cos) (1/sin)/(sin/cos) = (cos) (1/sin) (cos/sin) = (cos/sin)2


How do you simplify csc theta cot theta?

There are 6 basic trig functions.sin(x) = 1/csc(x)cos(x) = 1/sec(x)tan(x) = sin(x)/cos(x) or 1/cot(x)csc(x) = 1/sin(x)sec(x) = 1/cos(x)cot(x) = cos(x)/sin(x) or 1/tan(x)---- In your problem csc(x)*cot(x) we can simplify csc(x).csc(x) = 1/sin(x)Similarly, cot(x) = cos(x)/sin(x).csc(x)*cot(x) = (1/sin[x])*(cos[x]/sin[x])= cos(x)/sin2(x) = cos(x) * 1/sin2(x)Either of the above answers should work.In general, try converting your trig functions into sine and cosine to make things simpler.


How do you simplify csc theta minus cot x theta times cos theta plus 1?

There can be no significant simplicfication if some of the angles are theta and others are x, so assume that all angles are x. [csc(x) - cot(x)]*[cos(x) + 1] =[1/sin(x) - cos(x)/sin(x)]*[cos(x) + 1] =1/sin(x)*[1 - cos(x)]*[cos(x) + 1] =1/sin(x)*[1 - cos2(x)] =1/sin(x)*[sin2(x)] = sin(x)


Express csc theta in terms of cot theta theta is in quadrant 3?

It is -sqrt(1 + cot^2 theta)


What is cos theta multiplied by csc theta?

It is cotangent(theta).


How do you simplify sec x cot x?

sec(x)*cot(x) = (1/cos(x))*(cos(x)/sin(x)) = (1/sin(x)) = csc(x)


How do you simplify sin theta times csc theta divided by tan theta?

Since sin(theta) = 1/cosec(theta) the first two terms simply camcel out and you are left with 1 divided by tan(theta), which is cot(theta).


Can you simplify 1-cot x?

csc^2x+cot^2x=1


How do you simplify x x x?

sec(x)*cot(x) = (1/cos(x))*(cos(x)/sin(x)) = (1/sin(x)) = csc(x)


How do i simplify csc theta divided by sec theta?

By converting cosecants and secants to the equivalent sine and cosine functions. For example, csc theta is the same as 1 / sin thetha.


Verify that Cos theta cot theta plus sin theta equals csc theta?

It's easiest to show all of the work (explanations/identities), and x represents theta. cosxcotx + sinx = cscx cosx times cosx/sinx + sinx = csc x (Quotient Identity) cosx2 /sinx + sinx = csc x (multiplied) 1-sinx2/sinx + sinx = csc x (Pythagorean Identity) 1/sinx - sinx2/sinx + sinx = csc x (seperate fraction) 1/sinx -sinx + sinx = csc x (canceled) 1/sinx = csc x (cancelled) csc x =csc x (Reciprocal Identity)

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