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Q: What is sec squared theta times cos squared theta minus tan squared theta?

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- cos theta

You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.

There is a hint to how to solve this in what is required to be shown: a and b are both squared.Ifa cos θ + b sin θ = 8a sin θ - b cos θ = 5then square both sides of each to get:a² cos² θ + 2ab cos θ sin θ + b² sin² θ = 64a² sin² θ - 2ab sin θ cos θ + b² cos² θ = 25Now add the two together:a² cos² θ + a² sin² θ + b² sin² θ + b² cos² θ = 89→ a²(cos² θ + sin² θ) + b² (sin² θ + cos² θ) = 89using cos² θ + sin² θ = 1→ a² + b² = 89

sin/cos

(/) = theta sin 2(/) = 2sin(/)cos(/)

Related questions

Cos theta squared

- cos theta

cos(t) - cos(t)*sin2(t) = cos(t)*[1 - sin2(t)] But [1 - sin2(t)] = cos2(t) So, the expression = cos(t)*cos2(t) = cos3(t)

Zero. Anything minus itself is zero.

You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.

cosine (90- theta) = sine (theta)

1

cos2(theta) = 1 so cos(theta) = Â±1 cos(theta) = -1 => theta = pi cos(theta) = 1 => theta = 0

The question contains an expression but not an equation. An expression cannot be solved.

Until an "equals" sign shows up somewhere in the expression, there's nothing to prove.

sin squared

COS squared Theta + SIN squared Theta = 1; where Theta is the angles measurement in degrees.

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