- cos theta
You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.
Well, darling, if we square the first equation and the second equation, add them together, and do some algebraic magic, we can indeed show that a squared plus b squared equals 89. It's like a little math puzzle, but trust me, the answer is as sassy as I am.
sin/cos
(/) = theta sin 2(/) = 2sin(/)cos(/)
Cos theta squared
cos(t) - cos(t)*sin2(t) = cos(t)*[1 - sin2(t)] But [1 - sin2(t)] = cos2(t) So, the expression = cos(t)*cos2(t) = cos3(t)
- cos theta
Zero. Anything minus itself is zero.
You can use the Pythagorean identity to solve this:(sin theta) squared + (cos theta) squared = 1.
cosine (90- theta) = sine (theta)
1
cos2(theta) = 1 so cos(theta) = ±1 cos(theta) = -1 => theta = pi cos(theta) = 1 => theta = 0
The question contains an expression but not an equation. An expression cannot be solved.
Until an "equals" sign shows up somewhere in the expression, there's nothing to prove.
COS squared Theta + SIN squared Theta = 1; where Theta is the angles measurement in degrees.
Remember that tan = sin/cos. So your expression is sin/cos times cos. That's sin(theta).