How do you solve 2 sin2-5 sin plus 2 equals 0?

Answer 1

2*sin^2(x) - 5*sin(x) + 2 = 0 is a quadratic equation in sin(x).therefore,

{2*sin(x) - 1}*{sin(x) - 2)} = 0

=> sin(x) = 1/2 or sin(x) = 2

The second solution is rejected since sin(x) cannot exceed 1.

The principal solution is x = arcsin(1/2) = pi/6 radians. Additional or alternative solutions will depend on the domain for x - which has not been given.