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2*sin^2(x) - 5*sin(x) + 2 = 0 is a quadratic equation in sin(x).therefore,
{2*sin(x) - 1}*{sin(x) - 2)} = 0
=> sin(x) = 1/2 or sin(x) = 2
The second solution is rejected since sin(x) cannot exceed 1.
The principal solution is x = arcsin(1/2) = pi/6 radians. Additional or alternative solutions will depend on the domain for x - which has not been given.
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∙ 9y ago
lenpollock
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