Hope I'm right :P
2-x^(17)
Since 2 does not contain x, the derivative of 2 is 0.
(d)/(dx) 2-x^(17)=0+(d)/(dx) -x^(17)
To find the derivative of -x^(17), multiply the base (x) by the exponent (17), then subtract 1 from the exponent.
(d)/(dx) 2-x^(17)=0-17x^(16)
Combine all similar expressions.
(d)/(dx) 2-x^(17)=-17x^(16)
The derivative of 2-x^(17) is -17x^(16).
-17x^(16)
-21
-(3x -2) = 17 -3x + 2 = 17 - 3x = 15 x = -5
(3x-2)(x-2)
Assuming that by sticking a question mark after that equation, you wish to solve it for x, it can be done this way: x = x2 + 4x - 2 x2 + 3x = 2 x2 + 3x + 9/4 = 2 + 9/4 (x + 3/2)2 = (8 + 9)/4 x + 3/2 = ± √(17/4) x = -3/2 ± √17/2 x = (-3 ± √17) / 2
To solve x + 1.4 = 2, subtract 1.4 from each side; x = 0.6
-21
-(3x -2) = 17 -3x + 2 = 17 - 3x = 15 x = -5
2 - x > 17Add 'x' to each side:2 > 17 + xSubtract 17 from each side:-15 > xOr you could write . . .x < -15
(3x-2)(x-2)
11
== ==
Assuming that by sticking a question mark after that equation, you wish to solve it for x, it can be done this way: x = x2 + 4x - 2 x2 + 3x = 2 x2 + 3x + 9/4 = 2 + 9/4 (x + 3/2)2 = (8 + 9)/4 x + 3/2 = ± √(17/4) x = -3/2 ± √17/2 x = (-3 ± √17) / 2
x=12
There is a formula for the "difference of squares." In this case, the answer is (x - 17)( x + 17)
4
The equation to solve is given by. |-2 x + 2| -3 = -3 Add 3 to both sides of the equation and simplify. |-2 x + 2| = 0 |-2 x + 2| is equal to 0 if -2 x + 2 = 0. Solve for x to obtain. So, x = 1
That depends a great deal on the equation that x + 2 should be a part of. In order to solve for x, x + 2 needs to equal something. If x + 2 = 0, x = -2 If x + 2 = 4, x = 2