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3x2 + 10x - 8 = 0

3x2 + 12x - 2x - 8 = 0

3x(x + 4) - 2(x + 4) = 0

(3x - 2)(x + 4) = 0

So 3x - 2 = 0 or x + 4 = 0

so x = 2/3 or x = -4

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Q: How do you solve 3x squared plus 10x- 8 equals 0?
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