You find x. Oh! There it is!! ^ See?
They intersect at the point of: (-3/2, 11/4)
12x - 6 = 10x +2 12x - 10x = 2 + 6 2x = 8 x = 4
No solution in integers, quadratic formula gives roots as 6.73 & 3.27
Rearrange: x2 - 10x + 25 = 0ie (x - 5)(x - 5) = 0x = 5Check: x2 = 25; 10x - 25 = 50 - 25 = 25. Job done
2x+8x-2=22 10x-2=22 10x+2=+2 10x=24 10/10=24/10 x=2.4
10x+7=(-3) 10x=(-10) x=(-1)ans
(x + 5)(x + 5)
x=-8
You find x. Oh! There it is!! ^ See?
They intersect at the point of: (-3/2, 11/4)
12x - 6 = 10x +2 12x - 10x = 2 + 6 2x = 8 x = 4
There is no symbol between 7x and 31. Please resubmit using words eg "plus", "equals" etc.
No solution in integers, quadratic formula gives roots as 6.73 & 3.27
Rearrange: x2 - 10x + 25 = 0ie (x - 5)(x - 5) = 0x = 5Check: x2 = 25; 10x - 25 = 50 - 25 = 25. Job done
x2 + 9x2 = 10x2
Using the discriminant of b^2 -4ac = 0 the value of k works out as -2