Let c represent cos x.
Then, we have,
4c2 - 2 = 0; whence,
4c2 = 2,
c2 = ½, and
c = ±√½ = ±½√2; that is,
cos x = ±½√2.
From this, it is evident that,
for 0 ≤ x < 360°, x = 45°, 135°, 225°, or 315°;
or, if you prefer,
for 0 ≤ x < 2π, x = ¼π, ¾π, 1¼π, or 1¾ π.
If x squared -10 = 0 then x = the square root of 10
Solve using the quadratic formula
3x2-9x = 0 x(3x-9) = 0 x = 0 or x = 3
x = 25 / 3squared + 5
The limit is 0.
Solve this problem -x squared -40x- 80 =0
If x squared -10 = 0 then x = the square root of 10
Secant is 1 over cosine and cosine 0 equals 1.
Solve using the quadratic formula
3x2-9x = 0 x(3x-9) = 0 x = 0 or x = 3
x = 25 / 3squared + 5
The limit is 0.
X (x - 25) So X = 0 Or X = +25
x2 + 6x + 8 = 0 Solve for x.X = -2 or X = -4
By factoring. q2 + 16q = 0 q (q + 16) = 0 Now, either q = 0, or q + 16 = 0. Solve those two equations to get the solution.
x * x - 9 = 0 PEMDAS = Multiplication first. What multiplied it self equals nine? 3. So x = 3
0 squared is 0. Zero times zero equals zero.