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How do you solve the B in Ax plus By equals C?
To solve for B in the equation ( Ax + By = C ), you first isolate the term involving B. Rearranging gives ( By = C - Ax ). Then, divide both sides by y (assuming y is not zero) to solve for B: ( B = \frac{C - Ax}{y} ).
How do you solve a AND b OR c in logical operators?
There is nothing to "solve". You can evaluate the expression when each of a, b and c are TRUE or FALSE. But that is not solving.
Prove if a union c equals b union c and a intersect c equals b intersect c then a equals b?
suppose x is in B. there are two cases you have to consider. 1. x is in A. 2. x is not in A Case 1: x is in A. x is also in B. then x is in A intersection B. Since A intersection B = A intersection C, then this means x is in A intersection C. this implies that x is in C. Case 2: x is not in A. then x is in B. We know that x is in A union B. Since A union B = A union C, this means that x is in A or x is in C. since x is not in A, it follows that x is in C. We have shown that B is a subset of C. To show that C is subset of B, we do the same as above.
P equals b plus 3a plus c solve for b?
p=b+3a+c p-3a-c=b+3a-3a+c-c p-3a-c=b b=p-3a-c
What are angles formed by two intersecting lines and which are opposite of each other called?
All angles are formed by two intersecting lines. The pairs of angles opposite each other are called vertical angles. If two angles are vertical, they measure the exact same. Say you name the angles formed as A, B, C, and D. A and C are vertical and B and D are vertical. The angles next to each other formed by intersecting lines are supplementary, and add up to 180 degrees. That means A + B = 180 (since they are next to each other) and B+C = 180. Subtracting the first equation by the second equation gives us A + B - B - C = 180 - 180, which simplifies to A - C = 0, which further simplifies to A = C. The same can be said about B and D being equal.
How do you solve a equals b plus c plus d solve for c?
If: a = b+c+d Then: c = a-b-d
What is the complement of the union B and C?
not (b or c) = (not b) and (not c)
Is it true that if a union c equals b union c then a equals b?
No- this is not true in general. Counterexample: Let a = {1,2}, b = {1} and c ={2}. a union c = [1,2} and b union c = {1,2} but a does not equal b. The statement be made true by putting additional restrictions on the sets.
Solve the equation ax-b equals c for x?
ax - b = c ax = b + c x = (b + c)/a
How do you solve the B in Ax plus By equals C?
To solve for B in the equation ( Ax + By = C ), you first isolate the term involving B. Rearranging gives ( By = C - Ax ). Then, divide both sides by y (assuming y is not zero) to solve for B: ( B = \frac{C - Ax}{y} ).
How do you solve a AND b OR c in logical operators?
There is nothing to "solve". You can evaluate the expression when each of a, b and c are TRUE or FALSE. But that is not solving.
If j and k are intersecting lines A and B are points on j and C and D are points on k how many planes contain points A B C and D?
exactly one
Prove if a union c equals b union c and a intersect c equals b intersect c then a equals b?
suppose x is in B. there are two cases you have to consider. 1. x is in A. 2. x is not in A Case 1: x is in A. x is also in B. then x is in A intersection B. Since A intersection B = A intersection C, then this means x is in A intersection C. this implies that x is in C. Case 2: x is not in A. then x is in B. We know that x is in A union B. Since A union B = A union C, this means that x is in A or x is in C. since x is not in A, it follows that x is in C. We have shown that B is a subset of C. To show that C is subset of B, we do the same as above.
What is the formula to solve for b a equals 2b plus c?
If: a = 2b+c Then: a-c = 2b And: b = (a-c)/2
Prove A union B minus A intersection B equals A minus B union B minus A?
complement of c
Solve for indicated letter b equals 8c for c?
c equals b over 8
What A union C minus B equals A minus B union C minus B?
The expression ( (A \cup C) - B = (A - B) \cup (C - B) ) represents the set of elements that are in either ( A ) or ( C ) but not in ( B ). On the left side, ( (A \cup C) - B ) includes all elements from ( A ) and ( C ) excluding those in ( B ). The right side, ( (A - B) \cup (C - B) ), combines the elements in ( A ) without ( B ) and those in ( C ) without ( B ), which captures the same set of elements. Thus, both sides are equal, demonstrating a property of set difference and union.
