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Use Pythagoras' theorem:

102+122 = 244 and the square root of this is about 15.62049935' which is the distance.

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Q: How do you solve a 10' tree casts a 12' shadow how far is the top of the tree from tip of shadow?
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A 32 foot tall tree casts a shadow that is 48 feet long. How far away from the tree is a 6 foot tall person who is standing in the shadow of the tree as shown in the diagram?

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How high is a tree that casts a 24 ft shadow at the same time a 12 ft post casts a shadow which is 12 ft long?

As the sun is far enough away, the rays of light are effectively parallel. This produces similar triangles with the ratio of sides the same in each case. As the shadow of the post is 12 ft and the shadow of the tree is 24 ft, the sides of the triangle of the tree are double that of the post. Assuming the post is parallel to the tree, the tree's height is twice the height of the post → tree = 12 ft × 2 = 24ft high.


How high is a tree that casts a 38 ft shadow when at the same time a pole casts an 11 ft shadow?

The question cannot be answered on two counts:first of all, how "high" the tree is would mean how far off the ground the tree is, although the question probably meant how "tall" the tree ismore importantly, the question does not mention how tall the pole is, so it is not possible to determine how tall the tree is, even assuming that both the tree and the pole are at right angles to the groundAnswerThe ratio of the height of the pole (Hp) to the length o the shadow of the pole (Lsp) is the same as the ratio of the height of the tree (Ht) to the length of the shadow of the tree (Lst).SoHp/Lps = Ht/LstSo inserting the known data:Hp/11 = Ht/38Then reorganizing:Ht = 38/11 Hp = 3.45HpThe tree is 3.45 times the height of the pole


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