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It depends on the particular equation, of course.
You can use several tricks, including eliminating things outside the parentheses, and using the distributive property.
Here is one example:
2(x+3) = 10
Divide both sides by 2:
x + 3 = 5. (The remainder should be easy to solve.
Another soution, using the distributive property:
2(x+3) = 10
2x + 6 = 10
Again, I am assuming you know how to solve equations WITHOUT parentheses, so I won't give the full solution here.
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How do you solve for x in this equation x to the 3rd minus 2x to the parenthesis x-2 and a half end parenthesis plus x to the parenthesis x to the x end parenthesis?
What I mean by this equation is: x^3-2x^(x-2.5)+x^(x^x)
Do you always have to use the distributive property to solve algebra equations?
Yes, when there are parenthesis in an equation, you have to use the distibutive property.
How do you solve log sub 9 parenthesis a over 27 closed parenthesis equals x minus 2?
Your equation has two variables in it ... 'a' and 'x'. So the solution is a four-step process: 1). Get another independent equation that relates the same two variables. 2). Solve one of the equations for one of the variables. 3). Substitute that into the other equation, yielding an equation in a single variable. Solve that one for the single variable. 4). Substitute that value back into the first equation, and solve it for the second variable.
Solve 3 over 2 parenthesis 1 minus 5 parenthesis equals negative 6?
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multiply the whole equation by the number in the denominator
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How do you solve for x in this equation x to the 3rd minus 2x to the parenthesis x-2 and a half end parenthesis plus x to the parenthesis x to the x end parenthesis?
What I mean by this equation is: x^3-2x^(x-2.5)+x^(x^x)
Do you always have to use the distributive property to solve algebra equations?
Yes, when there are parenthesis in an equation, you have to use the distibutive property.
How do you solve log sub 9 parenthesis a over 27 closed parenthesis equals x minus 2?
Your equation has two variables in it ... 'a' and 'x'. So the solution is a four-step process: 1). Get another independent equation that relates the same two variables. 2). Solve one of the equations for one of the variables. 3). Substitute that into the other equation, yielding an equation in a single variable. Solve that one for the single variable. 4). Substitute that value back into the first equation, and solve it for the second variable.
Solve 3 over 2 parenthesis 1 minus 5 parenthesis equals negative 6?
3/2(1-5)=-6 3/2(-4)=-6 3/-8=-6 Not equal. This equation is a false equation. Unless a variable was meant to be in the equation, this equation is not equal.
How do you solve equations involving fractional coefficients?
multiply the whole equation by the number in the denominator
What are the parenthesis in an equation mean?
Do the work inside the parenthesis first.
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Parenthesis
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You expand the parenthesis out first. Then simplify the rest.
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Because this equation has four variables, it would require four unique equations involving only these four variables to solve.
