It depends on the particular equation, of course.
You can use several tricks, including eliminating things outside the parentheses, and using the distributive property.
Here is one example:
2(x+3) = 10
Divide both sides by 2:
x + 3 = 5. (The remainder should be easy to solve.
Another soution, using the distributive property:
2(x+3) = 10
2x + 6 = 10
Again, I am assuming you know how to solve equations WITHOUT parentheses, so I won't give the full solution here.
What I mean by this equation is: x^3-2x^(x-2.5)+x^(x^x)
Yes, when there are parenthesis in an equation, you have to use the distibutive property.
Your equation has two variables in it ... 'a' and 'x'. So the solution is a four-step process: 1). Get another independent equation that relates the same two variables. 2). Solve one of the equations for one of the variables. 3). Substitute that into the other equation, yielding an equation in a single variable. Solve that one for the single variable. 4). Substitute that value back into the first equation, and solve it for the second variable.
3/2(1-5)=-6 3/2(-4)=-6 3/-8=-6 Not equal. This equation is a false equation. Unless a variable was meant to be in the equation, this equation is not equal.
multiply the whole equation by the number in the denominator
Parentheses is when you are doing an equation, and you solve the problem.
What I mean by this equation is: x^3-2x^(x-2.5)+x^(x^x)
Yes, when there are parenthesis in an equation, you have to use the distibutive property.
Your equation has two variables in it ... 'a' and 'x'. So the solution is a four-step process: 1). Get another independent equation that relates the same two variables. 2). Solve one of the equations for one of the variables. 3). Substitute that into the other equation, yielding an equation in a single variable. Solve that one for the single variable. 4). Substitute that value back into the first equation, and solve it for the second variable.
3/2(1-5)=-6 3/2(-4)=-6 3/-8=-6 Not equal. This equation is a false equation. Unless a variable was meant to be in the equation, this equation is not equal.
multiply the whole equation by the number in the denominator
Do the work inside the parenthesis first.
1000 millimeters equal how many centimeters
What square root property is essential to solve any radical equation involving square root?
Parenthesis
You expand the parenthesis out first. Then simplify the rest.
Because this equation has four variables, it would require four unique equations involving only these four variables to solve.