velocity = distance/time
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vf2 = vi2 + 2ad, where vf is final velocity, vi is initial velocity, a is acceleration, and d is displacement. Solve for a.vf = vi + at, where t is time time. Solve for a.
Where a = (v-u)/t a is acceleration, v is final velocity u is initial velocity t is time so, u=v-at
AnswerAcceleration = v2 - v1.........................timeAverage Acceleration requires you to average the the initial velocity of your trials and the ending velocity of your trials. You must also find the average for your time trials. Once you achieve these numbers, just plug them into the above formula and you can solve for average acceleration.
If the initial velocity was zero then final velocity V = 2*S / t where S = distance covered and t = time it took Acceleration a = 2*S / t2 or a = (V - V0) / t where (V - V0) is change in velocity.
You have not provided enough information. To solve this problem, you will use the kinematics equations. Take a look at these equations, you will discover that you have too many unknowns to solve for.