In trig, the secant squared divided by the tangent equals the hypotenuse squared divided by the product of the opposite and adjacent sides of the triangle.
Details: secant = hypotenuse/adjacent (H/A) and tangent = opposite/adjacent (A/O);
Then secant2/tangent = (H2/A2)/(O/A) = H2/A2 x A/O = H2/AO.
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you solve secant angles when you have the hypotenuse and adjacent sides. sec=1/cos or, cos^-1 (reciprocal identity property) Tangent is solved when you have adjacent and opposite sides, or you can look at it as its what you use when you dont have the hypotenuse. tan=sin/cos or tan=opp/adj or tan=y/x
The question contains an expression but not an equation. You cannot solve an expression.
You cannot "solve" a mean squared deviation". You can calculate it or use it, but there is nothing to solve!
_t(5t squared t+)
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