In trig, the secant squared divided by the tangent equals the hypotenuse squared divided by the product of the opposite and adjacent sides of the triangle.
Details: secant = hypotenuse/adjacent (H/A) and tangent = opposite/adjacent (A/O);
Then secant2/tangent = (H2/A2)/(O/A) = H2/A2 x A/O = H2/AO.
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∙ 14y agoyou solve secant angles when you have the hypotenuse and adjacent sides. sec=1/cos or, cos^-1 (reciprocal identity property) Tangent is solved when you have adjacent and opposite sides, or you can look at it as its what you use when you dont have the hypotenuse. tan=sin/cos or tan=opp/adj or tan=y/x
The question contains an expression but not an equation. You cannot solve an expression.
You cannot "solve" a mean squared deviation". You can calculate it or use it, but there is nothing to solve!
The answer depends on the precise nature of the problem.
_t(5t squared t+)
you solve secant angles when you have the hypotenuse and adjacent sides. sec=1/cos or, cos^-1 (reciprocal identity property) Tangent is solved when you have adjacent and opposite sides, or you can look at it as its what you use when you dont have the hypotenuse. tan=sin/cos or tan=opp/adj or tan=y/x
It isn't clear what you want to solve for. To solve trigonometric equations, it often helps to convert other angular functions (tangent, cotangent, secant, cosecant) into the equivalent of sines and cosines. However, the details of course depend on the specific case.
Substitute secant(x)=1/cos(x) into your equation, and you should be able to solve from there.
The question contains an expression but not an equation. You cannot solve an expression.
You cannot "solve" a mean squared deviation". You can calculate it or use it, but there is nothing to solve!
The answer depends on the precise nature of the problem.
Solve this problem -x squared -40x- 80 =0
you use the the 3 trigonometry functions , sin=opposite divided by hypotenuse cos=adjacent divided by hypotenuse tan=opposite divided by adjacent these are used to work out angles and side lengths in right angle triangles only!!! sine,cosine,tangent :)
x=9 squared
_t(5t squared t+)
2+2/x/2+2/x^2=2+1/x+2/x^2
Yes, this is a perfectly legitimate thing to do in the trigonometric functions. I will solve all your math problems. Check my profile for more info.