Trig identity... sin/cos = tangent
In a right triangle, its Opposite/Hypotenuse I always use: Soh (sin, opposite/hypotenuse) Cah (cosine, adjacent/hypotenuse) Toa (tangent, opposite/adjacent) Hope this helped! :)
The inverse of the cosine is the secant.
If X and Y are sides of a right triangle, R is the hypoteneuse, and theta is the angle at the X-R vertex, then sin(theta) is Y / R and cosine(theta) is X / R. It follows, then, that X is R cosine(theta) and Y is R sin(theta)
sin2 + cos2 = 1 So, (1 - 2*cos2)/(sin*cos) = (sin2 + cos2 - 2*cos2)/(sin*cos) = (sin2 - cos2)/(sin*cos) = sin2/(sin*cos) - cos2/(sin*cos) = sin/cos - cos-sin = tan - cot
Tangent = sine/cosine provided that cosine is non-zero. When cosine is 0, then tangent is undefined.
you can use the sine, cosine, tangent formula.
Sine = -0.5 Cosine = -0.866 Tangent = 0.577
Yes, sine, cosine, tangent definitions are based on right triangles
It means for any right angle triangle:- sine = opposte/hypotenuse cosine = adjacent/hypotenuse tangent = opposite/adjacent
Cotangent is 1 / tangent. Since tangent is sine / cosine, cotangent is cosine / sine.
in trigonometry
No, it does not.
Trigonometry
The cosine is ±1/sqrt(5) = ±0.4472 (approx).
Sine of the angle to its cosine.
It is a FALSE statement.