What do you want it solved for ?
's' ? or 'b' ? or 'c' ?
Since this is the formula for the total effective resistance of two parallel resistors,
the inductance of two parallel coils, and the capacitance of two series capacitors,
as well as the "lensmaker's formula" that relates the image distance, object distance,
and focal length of a lens, it's probably the most useful to solve it for 's', and I will now
do so. I shall require total silence from members of the audience.
1/s = 1/b + 1/c
Multiply each side by 'bc':
bc/s = bc/b + bc/c
bc/s = c + b
Multiply each side by 's':
bc = s (c + b)
Divide each side by (c + b):
bc/(c+b) = s
This is the handy form that's easy to remember ... it's "the product over the sum".
(4/9) x = That's not an equation. If there were a number after the 'equals' sign, then we could calculate the value of 'x'. But as it is, there's no question there, so there's nothing to solve.
b = 14
This is an inequality equation in the form of: ii < xxii/viii which is the same as 2 < 22/8
The possibility of your next question being noob is approximately 29 over 16.
h/9=7 multiply both sides by 9 h=63
x equals 4 over 35
(4/9) x = That's not an equation. If there were a number after the 'equals' sign, then we could calculate the value of 'x'. But as it is, there's no question there, so there's nothing to solve.
b = 14
This is an inequality equation in the form of: ii < xxii/viii which is the same as 2 < 22/8
28/36 - 9/36 = 19/36
The possibility of your next question being noob is approximately 29 over 16.
h/9=7 multiply both sides by 9 h=63
h/(-3 - 7) = 10h/-10 = 10h = -100
-2y square exp power -2x-1
it is closer to 1 over 2 (.5). 6 over 11 equals approximately .55
Yes. It equals to 1 and 1 over 14 because you have to divide 15 by 14 which equals 1 and you are left with one so it becomes 1 and 1over 14
You cannot solve this single equation. You can either change the subject so that it gives x = 12/y or xy = 12, which is the equation of a rectangular hyperbola.