All you need to do on these is make the coefficient(number) of either variable the same, usually by multiplication, then add or subtract to eliminate that variable.
Using Y
As the coefficients of Y are the same, just add the equations:
3x - 2y = 11
x + 2y = 9
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4x + 0y = 20
4x = 20 , which means X = 5 and Y =2
Using X
3x - 2y = 11
x + 2y = 9
Multiply the second equation by 3 and subtract.
x + 2y = 9 becomes 3x + 6y = 27, and it is easiest to just subtract the first
3x + 6y = 27
- (3x - 2y = 11)
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0x +8y = 16
8y = 16 so Y = 2 and X = 5
Simultaneous equations.
The system is simultaneous linear equations
Another straight line equation is needed such that both simultaneous equations will intersect at one point.
It's a simultaneous equation and can be solved by elimination which works out as:- x = -4 and y = 1
By elimination: x = 3 and y = 0
The elimination method only works with simultaneous equations, hence another equation is needed here for it to be solvable.
Through a process of elimination and substitution the solutions are s = 8 and x = 5
Simultaneous suggests at least two equations.
Solving these simultaneous equations by the elimination method:- x = 1/8 and y = 23/12
Solving the above simultaneous equations by means of the elimination method works out as x = 2 and y = 3
Simultaneous equations.
The system is simultaneous linear equations
x = -3 y = -2
Solve this simultaneous equation using the elimination method after rearraging these equations in the form of: 3x-y = 5 -x+y = 3 Add both equations together: 2x = 8 => x = 4 Substitute the value of x into the original equations to find the value of y: So: x = 4 and y = 7
I notice that the ratio of the y-coefficient to the x-coefficient is the same in both equations. I think that's enough to tell me that their graphs are parallel. So they don't intersect, and viewed as a pair of simultaneous equations, they have no solution.
Another straight line equation is needed such that both simultaneous equations will intersect at one point.
The point of intersection of the given simultaneous equations of y = 4x-1 and 3y-8x+2 = 0 is at (0.25, 0) solved by means of elimination and substitution.