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How do you solve x2 plus 6x equals -9?
2x+6x=-9 => 8x=-9=> x=-8/9
Can you solve x2 plus 2x - 63 equals 0?
x2+2x-63 = 0 When factorised: (x-7)(x+9) = 0 Therefore: x = 7 or x = -9
How do you solve x plus 6 equals 2x-9?
x + 6 = 2x - 9 Add 9 to both sides: x + 15 = 2x Subtract 1x from both sides: 15 = 1x or 15 = x
Solve 8x plus 39 equals 2x-15?
8x+39 = 2x-15 6x = -54 x = -9
How do you solve x2-81 equals 0?
2x - 81 = 0 Add 81 to both sides. 2x - 81 + 81 = 0 + 81 Substitute, -81 + 81 cancels out. 2x = 81 Divide by 2. x = 40.5 Above answer would be correct if your question was 2x but it was x2 so using the same method you would get x2 = 81 here the opposite of the square is the square root x = 9
How do you solve this trinomial x2-2x-63?
Simplifying x2 + -2x + -63 Reorder the terms: -63 + -2x + x2 Factor a trinomial. (-7 + -1x)(9 + -1x) Final result: (-7 + -1x)(9 + -1x)
How do you solve x2 plus 6x equals -9?
2x+6x=-9 => 8x=-9=> x=-8/9
What is the Factor x2 plus 2x 63?
x2+2x-63 = (x-7)(x+9) when factored
Can you solve x2 plus 2x - 63 equals 0?
x2+2x-63 = 0 When factorised: (x-7)(x+9) = 0 Therefore: x = 7 or x = -9
How do you solve x plus 6 equals 2x-9?
x + 6 = 2x - 9 Add 9 to both sides: x + 15 = 2x Subtract 1x from both sides: 15 = 1x or 15 = x
Solve 8x plus 39 equals 2x-15?
8x+39 = 2x-15 6x = -54 x = -9
How do you solve 2x 9x?
multiply the nos., 2(9), the answer is 18. then, multiply the variables, x(x), the answer is x2 so the answer is: 18x2
What is the factor of 3x2 2x 2 equals 0?
3x2 + 2x + 2 = 0 Can not be factored. You can however solve it for x: 3x2 + 2x = -2 x2 + 2x/3 = -2/3 x2 + 2x/3 + 1/9 = -2/3 + 1/9 (x + 1/9)2 = -5/9 x + 1/9 = ±√(-5/9) x = -1/9 ± i√(5/9) x = -1/9 ± i√5 / 3 x = -1/9 ± 3i√5 / 9 x = (-1 ± 3i√5) / 9
How do you solve x2-81 equals 0?
2x - 81 = 0 Add 81 to both sides. 2x - 81 + 81 = 0 + 81 Substitute, -81 + 81 cancels out. 2x = 81 Divide by 2. x = 40.5 Above answer would be correct if your question was 2x but it was x2 so using the same method you would get x2 = 81 here the opposite of the square is the square root x = 9
Solve 2x 39x?
2x - 3= 9 x=
How would you solve 2x plus 1 equals 9?
2x+1 = 9 2x = 9-1 2x = 8 x = 4
Solve 2x-3 equals 9?
2x-3=9 so 2x=12 and x=6
