0
x2 + 3x - 1 is an expression, NOT an equation so, as it stands, there is nothing to solve.
If the equation was the above expression = 0, then using the quadratic equation,
x = [-3 ± sqrt(9 + 4*1*1)]/2
= [-3 ± sqrt(13)]/2
= -0.30278 and 3.30278 (to 5 dp)
What else can I help you with?
How do you solve x2 plus 3x4?
This is an expression and you do not solve an expression, but you can factor this one.X2 + 3X4X2(1 + 3X2)========
How do you solve x-1 plus x2-x plus x3-x2 plus x4-x3?
x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.
Solve the equation y' plus x2y equals x2?
(2x)ysquared
Solve x2 plus 10x plus 25?
(x+5)^2 and therefore x = -5
How do you solve the equation. X2 plus y2 plus z2 - 4x plus 4y plus 2z plus 5 equals 0 x2 plus y2 plus z2 equals 4?
(2-r)e-rr
How do you solve x2 plus 7x plus 12?
You cannot solve, without equating it to something. As given it is just an expression. However it can be factored. x^(2) + 7x +12 ( x + 3)(x + 4) Factored but NOT solved. However, it we equate to 'zero(0)' then it can be solved. ( x + 3)( x + 4) = 0 X + 3 = 0 x = -3 Similarly x + 4 = 0 x = -4 Are the solutions (solved).
How do you solve x2 plus 3x plus 3 0?
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
How do you solve x2 plus 3x4?
This is an expression and you do not solve an expression, but you can factor this one.X2 + 3X4X2(1 + 3X2)========
Consider the following linear programming problem Max Z equals 3x1 plus 2x2?
Given the limited information in the question, Z is maximised when x1 or x2 (or both) are maximised. There is no trade-off between x1 and x2 to worry about.
How do you solve X2 plus x-132?
-130
How do you solve x-1 plus x2-x plus x3-x2 plus x4-x3?
x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.
Solve the equation y' plus x2y equals x2?
(2x)ysquared
Solve x2 plus 10x plus 25?
(x+5)^2 and therefore x = -5
How do you solve the equation. X2 plus y2 plus z2 - 4x plus 4y plus 2z plus 5 equals 0 x2 plus y2 plus z2 equals 4?
(2-r)e-rr
X2 plus 5x plus 6 how to solve?
x2+5x+6 = (x+2)(x+3) when factored because 2 and 3 are factors of 6
Solve for x -10 -x2 plus 2x-6?
You will need to use the FOIL formula to solve this type of equation.
X2 plus 7x plus 11 equals 11x plus 9 solve quadratic?
x=4 x=0
