This requires solving a quadratic.
Let one number be x
The other number is (10-x)
Their product is:
x(10-x) = 22
10x - x² = 22
x² -10x + 22 = 0
Now apply the quadratic formula:
b² - 4ac = 100 - 88 = 12
x = (10 ± √12)/2
since √12 = 2√3
x = 5 ±√3
So the two numbers are:
5+√3 and 5-√3
Sum is 10 (check)
Product is 25-3 = 22 (check)
One possibility: IV+IV+IV = XII using Roman numerals
No.
000
Two Numbers consisting only of ones that when multiplied or added equal the same number are 11, and 1.1
1, 2 and 3
2 and 2
remains the same
because when you add numbers if you move them around then the quantaty of the numbers is still the same making it add up to the same number
The product of two numbers is the proceeding result when two numbers are added together.
Only true if both of the numbers are of the same polarity.
The answer will depend on same as WHAT!
1, 2 and 3