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This requires solving a quadratic.

Let one number be x

The other number is (10-x)

Their product is:

x(10-x) = 22

10x - x² = 22

x² -10x + 22 = 0

Now apply the quadratic formula:

b² - 4ac = 100 - 88 = 12

x = (10 ± √12)/2

since √12 = 2√3

x = 5 ±√3

So the two numbers are:

5+√3 and 5-√3

Sum is 10 (check)

Product is 25-3 = 22 (check)

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โˆ™ 2014-02-16 07:27:55
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Q: What can be added to get 10 and mulitplied to get 22 using the same numbers?
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