y = x2 - 3x - 20 is a formula linking two variables, x and y. It does not - indeed, it cannot - have a solution.
The equation x2 - 3x - 20 = 0 has solutions at x = -3.217 and x = 6.217 approx.
Solve using the quadratic formula
You cant solve it unless it is an equation. To be an equation it must have an equals sign.
Solve, using the Rule of 72 rate = 4%, years = 18, fv=$8,000. Solve for PV. Formula: PV = $1/(1+r) t PV = $8000/(1+.04) 18 PV = $8000/2.0258 3949.03 = $8000/2.20258
(2,-2)
Since the second equation is already solved for "y", you can replace "y" by "9" in the other equation. Then solve the new equation for "x".
Solve using the quadratic formula
8840-026
You cant solve it unless it is an equation. To be an equation it must have an equals sign.
You can solve lineaar quadratic systems by either the elimination or the substitution methods. You can also solve them using the comparison method. Which method works best depends on which method the person solving them is comfortable with.
Solve, using the Rule of 72 rate = 4%, years = 18, fv=$8,000. Solve for PV. Formula: PV = $1/(1+r) t PV = $8000/(1+.04) 18 PV = $8000/2.0258 3949.03 = $8000/2.20258
the answer
(2,-2)
a=5: c=4
Since the second equation is already solved for "y", you can replace "y" by "9" in the other equation. Then solve the new equation for "x".
a2+30a+56=0 , solve for a Using the quadratic formula, you will find that: a=-2 , a=-28
You cannot solve one linear equation in two variables. You need two equations that are independent.
3(5x-2y)=18 5/2x-y=-1