If the second digit is 1, 2, 3 or 4 replace it by 0.
If the second digit is 6, 7, 8 or 9 replace it by 0 and increase the first digit by 1.
If the second digit is 5, then,
if the first digit is even, replace the second digit by 0,
if the first digit is odd, replace the second digit by 0 and increase the first digit by 1.
Many people will require that 5 as the second digit should be treated the same as 1-4. This ignores the upward bias introduced and IEEE 754 standard for rounding.
421 and 842
The two-digit positive integers with a tens digit of 3 are: 30 31 32 33 34 35 36 37 38 39
there are no 3 digit tis two digit! :) * * * * * 90 of them.
81
19?
421 and 842
There are 45 of them.
The two-digit positive integers with a tens digit of 3 are: 30 31 32 33 34 35 36 37 38 39
there are no 3 digit tis two digit! :) * * * * * 90 of them.
The answer depends on what the tens digit is greater than, and what the ones digit does then.
The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.
81
40, 51, 62, 73, 84, and 95
Oh, what a lovely question! If we're looking for 2-digit numbers where the one's digit is greater than the ten's digit, we simply need to think about the possibilities. There are 36 such numbers, ranging from 12 to 98. Just imagine all the happy little numbers waiting to be discovered!
When you add tens to the tens digit and ones it goes ten more.
For the tens digit to be a prime number then it must equal 2, 3, 5 or 7. There are four 3-digit prime numbers that fit the above condition and also have the tens and units digits forming a 2-digit prime number. 131, 137, 173, 179. The person supplying the question may like to sum the various combinations.
The number can be any one of these four numbers:640751862973