The sequence is too short to be certain but it could be
tn = (n-1)2 + n2 = 2n2 -2n + 1
[ 25 - 6n ] is.
This is the Fibonacci sequence, where the number is the sum of the two preceding numbers. The nth term is the (n-1)th term added to (n-2)th term
The nth term is: 5-2n
T(n) = 25 - 6n
(2n-1)(-1)n
The nth term is: 5-6n
The nth term is: 3n+1 and so the next number will be 16
what will the eight number be. 1, 7, 13, 19, 25, 31 ...
The given sequence is an arithmetic sequence with a common difference of 6. To find the nth term of this sequence, we can use the following formula: nth term = first term + (n - 1) x common difference where n is the position of the term we want to find. In this sequence, the first term is 1 and the common difference is 6. Substituting these values into the formula, we get: nth term = 1 + (n - 1) x 6 nth term = 1 + 6n - 6 nth term = 6n - 5 Therefore, the nth term of the sequence 1, 7, 13, 19 is given by the formula 6n - 5.
1+3n
I suspect that the first term should be "negative 3", ie the sequence is -3, 1, 5, 9, 13, 17, ... The nth term is 4n - 7
3n-2
2n+1
[ 25 - 6n ] is.
The nth term is 4n - 3
This is the Fibonacci sequence, where the number is the sum of the two preceding numbers. The nth term is the (n-1)th term added to (n-2)th term
The (n)th term = the (n - 1)th term + (2n + 1)