Since there are no powers of x or y or trigonometric functions or anything like that, you know that the graph is a straight line. So two points on the line is all that you need.
Step 1:
Let x = 0
and find y from the equation: y = -0 + 3 = 3
so one point on the graph (the y-intercept) is (0, 3)
Step 2:
Let x = 5 (or any other number)
and find y from the equation: y = -5 + 3 = -2
so another point on the graph is (5, -2)
Step 3:
Join the two points.
Done!
3
y=3x+(3/2), so the slope is 3 or (3/1).
bend over and ill show you
The multiplication by 3 increases the magnitude, and the + 3 shifts the graph upward to be "centred" at y = 3. The graph now oscillates between 6 and 0 (3 + 3, 3 - 3).
A straight line, passing through the point (0,5) with a gradient of -3.
3
down
A graph that has 1 parabolla that has a minimum and 1 positive line.
2,4
First, reflect the graph of y = x² in the x-axis (line y = 0) to obtain the graph of y = -x²; then second, shift it 3 units up to obtain the graph of y = -x² + 3.
Upwards.
y=-10x-4
Draw a circle with its center at the origin and a radius of 3.
y=3x+(3/2), so the slope is 3 or (3/1).
You may mean, what is the graph of the function y = x^2 + 3. This graph shows a upward parabola with a y-intercept of 3 and a minimum at x=0.
First of all, if 'x' is 3, then 'x' doesn't equal -3x+3 . You must mean y = -3x + 3.If x=3, then (-3x + 3) = -6 .The graph is the point (3, -6) .
bend over and ill show you