To find the length of the diagonal in a rectangle, use the formula for calculating the hypotenuse of a right triangle: a² = b² + c². a² = 3² + 10² a² = 9 + 100 a² = 109 a = 10.44 m
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
If the only known fact is the length of the diagonal then the width and length of the rectangle CANNOT be determined. The diagonal could be that of a square, or of a rectangle that is very long but quite narrow. Consequently at least one more fact is required such as; the dimension of either the length or the width, or the angle that the diagonal makes to the base of the rectangle or even the area of the rectangle.
15 cm for the diagonal.
Using Pythagoras' theorem it is 26 inches in length
You use the pythagorous theorm to calculate the hypotenuse of the triangle, which is the same line as the diagonal. 7(7)+ 10(10)= diagonal x diagonal 149= diagonal x diagonal Diagonal= square root of 149: this approximates to 12.207in Visit quickanswerz.com for more math help/tutoring! Consider a rectangle with dimensions 7 inches by 10 inches. Let ABCD be the rectangle. We need to find the length of the diagonal. We know that the diagonals of a rectangle are same in length. So, it is enough to find the length of the diagonal BD. From the rectangle ABCD, it is clear that the triangle BCD is a right angled triangle. So, we can find the length of the diagonal using the Pythagorean Theorem. BD2 = BC2 + DC2 BD2 = 102 + 72 BD2 = 100 + 49 BD2 = 149 BD = √149 BD = 12.207 So, the length of the diagonal is 12.21 inches. Source: www.icoachmath.com
Other than what? It really all depends on what is given. For example:If you know the length of one diagonal, the other is just as long.If you know the length and width of the rectangle, use Pythagoras' formula for the diagonal.If you know one of the sides of the rectangle, and an angle, use some basic trigonometry to find the diagonal.
Approximately 15.62 feet.
15 inches (solved with the help of Pythagoras' theorem)
Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764
Length of a long side x length of a short side = area
If the length of a rectangle is 12 and the width of the rectangle is 16, by the Pythagorean theorem we know that one diagonal is 20 units long. You can draw two diagonals within a rectangle, so the length of both diagonals together is 20+20 = 40 units.
15 cm Solved through Pythagoras' theorem.
The diagonal is 47.707'
The diagonal is 48.877 feet.
The diagonal would be 12.53 meters.
The diagonal is 22.203 centimeters.
The diagonal is 221.2 inches long.
The diagonal is 3.231 meters.
The diagonal is 14.21 cm
The diagonal is 15.652'
The diagonal will be the hypotenuse of a right triangle with legs 30 and 34 feet So its length is the square root of (34^2+ 30^2 )
By Pythagoras, the length of the diagonal = sqrt[(1.8)2 + (1.2)2] = sqrt[3.24 + 1.44] = sqrt[4.68] = 2.16 m
The diagonal is 100'