2 to the 7th power = 128 * * * * * No. That is the total number of combinations, consisting of any number of elements. The number of 2 number combinations is 7*6/2 = 21
No. The number of permutations or combinations of 0 objects out of n is always 1. The number of permutations or combinations of 1 object out of n is always n. Otherwise, yes.
There are 5,461,512 such combinations.
There are infinitely many numbers and so infinitely many possible combinations.
The number of combinations - not to be confused with the number of permutations - is 2*21 = 42.
The number of combinations of 6 letters is 6! or 720.
The whole point of combinations is that the order of the number (or items) does not matter. Once you specify what the second number is, you are no longer looking at combinations.
2 to the 7th power = 128 * * * * * No. That is the total number of combinations, consisting of any number of elements. The number of 2 number combinations is 7*6/2 = 21
No. The number of permutations or combinations of 0 objects out of n is always 1. The number of permutations or combinations of 1 object out of n is always n. Otherwise, yes.
There are 4845 combinations.
252 combinations, :)
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
There are 6C3 = 20 such combinations.
There are 5,461,512 such combinations.
Since a number can have infinitely many digits, there are infinitely many possible combinations.
This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.
just intrested in the number combinations * * * * * Number of combinations = 56C6 = 56*55*54*53*52*51/(6*5*4*3*2*1) = 32,468,436