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To calculate the number of 12-number combinations using numbers 1-36, we can use the formula for combinations: nCr = n! / r!(n-r)!, where n is the total number of items to choose from (36) and r is the number of items to choose (12). Plugging in the values, we get 36C12 = 36! / 12!(36-12)! = 36! / 12!24! = (363534*...25) / (121110...*1). This simplifies to 125,736,770 unique combinations.
There are 12C4 4 NUMBER combinations. And that equals 12*11*10*9/(4/3/2/1) = 495 combinations. However, some of these, although 4 number combinations consist of 7 digits eg 1, 10, 11, and 12. Are you really sure you want 4-DIGIT combinations?
The number of combinations of N things taken P at a time is (N! - P!) / (N - P)! The number of combinations of 24 things taken 12 at a time is 1,295,295,050,649,599.
1 and 11 and 21 and 31 and 42 and 12 and 22 and 32 and 43 and 13 and 23 and 33 and 44 and 14 and 24 and 34 and 416 combinations
12 how come
There are 24C12 = 24!/[12!*12!] = 2,704,156 combinations.
To calculate the number of 12-number combinations using numbers 1-36, we can use the formula for combinations: nCr = n! / r!(n-r)!, where n is the total number of items to choose from (36) and r is the number of items to choose (12). Plugging in the values, we get 36C12 = 36! / 12!(36-12)! = 36! / 12!24! = (363534*...25) / (121110...*1). This simplifies to 125,736,770 unique combinations.
There are 12C4 4 NUMBER combinations. And that equals 12*11*10*9/(4/3/2/1) = 495 combinations. However, some of these, although 4 number combinations consist of 7 digits eg 1, 10, 11, and 12. Are you really sure you want 4-DIGIT combinations?
about 12
To calculate the number of 4-digit combinations you can get from the numbers 1, 2, 2, and 6, we need to consider that the number 2 is repeated. Therefore, the total number of combinations is calculated using the formula for permutations of a multiset, which is 4! / (2!1!1!) = 12. So, there are 12 unique 4-digit combinations that can be formed from the numbers 1, 2, 2, and 6.
12 Combinations.
There are 24C12 = 24*23*...*13/(12*11*...*1) = 2,704,156 combinations.
do you mean how many combinations of any size? So we have 12 combinations of size 1 12C2=12x11/2 =66 of size 2 12C3 of size 3 and we keep going and need to add these. But there is a formula for adding all these. Think of the each number between 1 and 12, say 1, for any combination it is either in that combination of not in it. So we have 2^12 combinations. That is 4096
The number of combinations of N things taken P at a time is (N! - P!) / (N - P)! The number of combinations of 24 things taken 12 at a time is 1,295,295,050,649,599.
Only three: 12, 13 and 23. Remember that the combinations 12 and 21 are the same.
1 and 11 and 21 and 31 and 42 and 12 and 22 and 32 and 43 and 13 and 23 and 33 and 44 and 14 and 24 and 34 and 416 combinations
30