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How many different three digit numbers can you form using the digits 1 2 3 5 6 7 and 9 without repetition?
There are seven possible digits for the first digit and 6 digits for the second (minus one digit for the digit used as the first digit) and 5 options for the last digit (minus one again for the second digit) and then you just multiply them all together to get a total possible combination of 210 numbers that are possible.
How many 6 digit numbers can be formed using the digits 123456789?
There are 60480 numbers.
How many 3 digit numbers can you make using the numbers 6 7and 8 if the digits can be repeated?
If you only use each digit once the number is 6 (it is a simple permutation and 3!=6). If you can repeat the digits there are 9 possible 3-digit numbers that start with 6, 9 that start with 7, and 9 that start with 8, giving you 27 possibilities.
How many two digit numbers can you form using the digits 1235679 with repetition allowed?
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
What are the possible sequence variations of a 5 digit sequence using the numbers 1 to 6 when the first 3 digits in the sequence are 345?
if repeating is allowed... 36 (6x6, for the last two digits) If not, 6 (3x2, last two digits)
