There are 4 possible numbers if the digits are not repeated; 18 if they are. Those are 3-digit numbers, assuming that zero would not be a leading digit. If zero is allowed for a leading digit, then you can have 6 for the non repeated, and 27 if repetition.
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There are seven possible digits for the first digit and 6 digits for the second (minus one digit for the digit used as the first digit) and 5 options for the last digit (minus one again for the second digit) and then you just multiply them all together to get a total possible combination of 210 numbers that are possible.
There are 60480 numbers.
If you only use each digit once the number is 6 (it is a simple permutation and 3!=6). If you can repeat the digits there are 9 possible 3-digit numbers that start with 6, 9 that start with 7, and 9 that start with 8, giving you 27 possibilities.
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
if repeating is allowed... 36 (6x6, for the last two digits) If not, 6 (3x2, last two digits)