0
There are 4 possible numbers if the digits are not repeated; 18 if they are. Those are 3-digit numbers, assuming that zero would not be a leading digit. If zero is allowed for a leading digit, then you can have 6 for the non repeated, and 27 if repetition.
Add your answer:
Earn +20 pts
How many different three digit numbers can you form using the digits 1 2 3 5 6 7 and 9 without repetition?
There are seven possible digits for the first digit and 6 digits for the second (minus one digit for the digit used as the first digit) and 5 options for the last digit (minus one again for the second digit) and then you just multiply them all together to get a total possible combination of 210 numbers that are possible.
How many 6 digit numbers can be formed using the digits 123456789?
There are 60480 numbers.
How many 3 digit numbers can you make using the numbers 6 7and 8 if the digits can be repeated?
If you only use each digit once the number is 6 (it is a simple permutation and 3!=6). If you can repeat the digits there are 9 possible 3-digit numbers that start with 6, 9 that start with 7, and 9 that start with 8, giving you 27 possibilities.
How many 3 digit numbers can be made using 3 6 and 9 if digits can be repeated?
When creating a 3-digit number using the digits 3, 6, and 9, with repetition allowed, each digit has 3 possible choices. Therefore, the total number of 3-digit numbers that can be formed is calculated by multiplying the number of choices for each digit, which is 3x3x3 = 27. So, there are 27 different 3-digit numbers that can be made using the digits 3, 6, and 9 with repetition allowed.
How many two digit numbers can you form using the digits 1235679 with repetition allowed?
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
How many different 3-digit numbers less than 500 can be made using the digits 345 and 6 if the digits can be only used only once?
There are 2 possible digits for the first digit (3 or 4), leaving 3 possible digits for the second digit (5 and 6 and whichever was not chosen for the first), leaving 2 possible digits for the third. Thus there are 2 × 3 × 2 = 12 possible 3 digit numbers.
How many 3-digit numbers using the digits 0-7 are possible if repetition are allowed?
290
What are the the 3 digit numbers using 1345678?
Using the digits of 1345678, there are 210 three digit numbers in which no digit is repeated.
How many different three digit numbers can you form using the digits 2 5 and 7?
6 possible 3 digit combonations
How many 2-digit numbers can be formed using the digits 1 3 7 if repetition of digits is allowed?
Possible solutions - using your rules are:- 11,13,17,31,33,37,71,73 &77
How many different three digit numbers can you form using the digits 1 2 3 5 6 7 and 9 without repetition?
There are seven possible digits for the first digit and 6 digits for the second (minus one digit for the digit used as the first digit) and 5 options for the last digit (minus one again for the second digit) and then you just multiply them all together to get a total possible combination of 210 numbers that are possible.
How many possible 5 digit combinations are there using 5 digits?
Possible 5 digit combinations using 5 digits only 1 time is 5! or 5*4*3*2*1 or 120. Using 5 digits where numbers can be used 5 times is 55 or 3125.
How many two digit numbers can be formed from the digits 7341 if none of the digit can be repeated?
There are twelve possible solutions using the rule you stated... 13,14,17,31,34,37,41,43,47,71,73 & 74
How many four digits numbers can be formed using 0123456789?
Assuming that the first digit of the 4 digit number cannot be 0, then there are 9 possible digits for the first of the four. Also assuming that each digit does not need to be unique, then the next three digits of the four can have 10 possible for each. That results in 9x10x10x10 = 9000 possible 4 digit numbers. If, however, you can not use the same number twice in completing the 4 digit number, and the first digit cannot be 0, then the result is 9x9x8x7 = 4536 possible 4 digit numbers. If the 4 digit number can start with 0, then there are 10,000 possible 4 digit numbers. If the 4 digit number can start with 0, and you cannot use any number twice, then the result is 10x9x8x7 = 5040 possilbe 4 digit numbers.
How many 6 digit numbers can be formed using the digits 123456789?
There are 60480 numbers.
How many even four digit numbers can be made using 02356 where the first digit is cannot be 0 and no digits are repeated?
Assuming that 2356 is a different number to 2365, then: 1st digit can be one of four digits (2356) For each of these 4 first digits, there are 3 of those digits, plus the zero, meaning 4 possible digits for the 2nd digit For each of those first two digits, there is a choice of 3 digits for the 3rd digit For each of those first 3 digits, there is a choice of 2 digits for the 4tj digit. Thus there are 4 x 4 x 3 x 2 = 96 different possible 4 digit numbers that do not stat with 0 FM the digits 02356.
