The first digit can be 7, 6, or 5 . . . . 3 choices. For each one . . .
The second digit can be 7, 6, 5, or 0 . . . . 4 choices. For each one . . .
The third digit can be 7, 6, 5, or 0 . . . . 4 choices.
The total number of possibilities is (3 x 4 x 4) = 48
If it's OK to have '0' as the first digit, then there are 64 possibilities.
It is 10000.
repetition
The number of combinations you can make with the digits 1234567890 depends on how many digits you want to use and whether repetition is allowed. If you use all 10 digits without repetition, there are 10! (10 factorial) combinations, which equals 3,628,800. If you are choosing a specific number of digits (for example, 3), the number of combinations would be calculated using permutations or combinations based on the rules you set.
There are 2000 such numbers.
10 30 80
It is 10000.
24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.
Just six numbers... 345, 354, 435, 453, 534 & 543
repetition
There are 2000 such numbers.
The number of combinations you can make with the digits 1234567890 depends on how many digits you want to use and whether repetition is allowed. If you use all 10 digits without repetition, there are 10! (10 factorial) combinations, which equals 3,628,800. If you are choosing a specific number of digits (for example, 3), the number of combinations would be calculated using permutations or combinations based on the rules you set.
There are 2000 such numbers.
10 30 80
Since there are only 3 digits available, repetition must be allowed. In that case, there are 30 combinations.
33 = 27 with repetition, 3! = 3*2*1 = 6 without repetition.
7432
To be irrational, it would have to have an infinite number of digits, without a periodic repetition.