Answer: 2058
Explanation: Consider the thousandths place. You can place digits 1,2,3,4,5,6 (not 0 as the number would then become a 3-digit).
Now consider hundredths place. You can place all the allowed digits ( ie, 0,1,2,3,4,5,6).
In the same way you can place all allowed digits in tens and ones place.
No. of digits which can be placed in thousandths place: 6
No. of digits which can be placed in hundredths place: 7
No. of digits which can be placed in tens place: 7
No. of digits which can be placed in ones place: 7
Total possible numbers which can be formed: 6 X 7 X 7 X 7 = 2058
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
Possible solutions - using your rules are:- 11,13,17,31,33,37,71,73 &77
It is 415968.
9*8*7 = 504 of them.
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.
-123456787
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
290
Possible solutions - using your rules are:- 11,13,17,31,33,37,71,73 &77
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
There are 4 possible numbers if the digits are not repeated; 18 if they are. Those are 3-digit numbers, assuming that zero would not be a leading digit. If zero is allowed for a leading digit, then you can have 6 for the non repeated, and 27 if repetition.
30 without repetition (6P2) 66 with repetition (12C2)
It is 415968.
9*8*7 = 504 of them.
10^7 if the repetition of digits is allowed. 9*8*7*6*5*4*3 , if the repetition of digits is not allowed.