Obviously, you must let me repeat numbers. If you didn't, then I couldn't make
any 4-number combinations out of only 3 numbers.
The first number can be any one of 3. ( 9, 2, or 0). For each of those . . .
The second number can be any one of 3. For each of those . . .
The third number can be any one of 3. For each of those . . .
The fourth number can be any one of 3.
So the total number of possible combinations is (3 x 3 x 3 x 3) = 81 .
The number of combinations of six numbers that can be made from seven numbers will depend on if you can repeat numbers. In all there are over 2,000 different numbers that can be made.
9!/5! or 3024
8C6 = 28
2 to the 7th power = 128 * * * * * No. That is the total number of combinations, consisting of any number of elements. The number of 2 number combinations is 7*6/2 = 21
None. You do not have enough numbers to make even one combination.
The number of combinations of six numbers that can be made from seven numbers will depend on if you can repeat numbers. In all there are over 2,000 different numbers that can be made.
9!/5! or 3024
8C6 = 28
2 to the 7th power = 128 * * * * * No. That is the total number of combinations, consisting of any number of elements. The number of 2 number combinations is 7*6/2 = 21
252 combinations, :)
None. You do not have enough numbers to make even one combination.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
20
There are 8,592,039,666 combinations of 6 numbers out of 138 numbers, like the numbers from 1 to 138.
There are a huge number of combinations of 5 numbers when using the numbers 0 through 10. There are 10 to the 5th power combinations of these numbers.
If every number can be used as many times as you like, there are 104 = 10000 different combinations. If each number can only be used once, there are 9!/(9 - 4)! = 5040 combinations.
There are infinitely many numbers and so infinitely many possible combinations.