Obviously, you must let me repeat numbers. If you didn't, then I couldn't make
any 4-number combinations out of only 3 numbers.
The first number can be any one of 3. ( 9, 2, or 0). For each of those . . .
The second number can be any one of 3. For each of those . . .
The third number can be any one of 3. For each of those . . .
The fourth number can be any one of 3.
So the total number of possible combinations is (3 x 3 x 3 x 3) = 81 .
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The number of combinations of six numbers that can be made from seven numbers will depend on if you can repeat numbers. In all there are over 2,000 different numbers that can be made.
9!/5! or 3024
8C6 = 28
None. You do not have enough numbers to make even one combination.
2 to the 7th power = 128 * * * * * No. That is the total number of combinations, consisting of any number of elements. The number of 2 number combinations is 7*6/2 = 21