It depends on whether the order of the numbers matters. For example, if 1234 and 2413 are considered to be the same combination or not. It also depends on whether the numbers can be used more than once. There is a different procedure for each case. To find out how many unique combinations there are, first lay out four blank spaces (since the combinations are 4 numbers long) with multiplication symbols between them. ______ * ______ * ______ * ______ Then, since there are 6 choices for the first spot, put a six on it. If it's okay to re-use digits, the second spot will also have a 6, as will the third and fourth spots. If it's not okay to re-use digits, the numbers would be 6*5*4*3 since the number of choices is being lowered every time one is chosen. 6*6*6*6 = 1296 unique combinations with repetition allowed
654321-100000= 554321 combinations
You Can Create 999 Number combinations
9999
There are infinite combinations that can make 3879
Assuming the digits cannot be repeated, there are 7 combinations with 1 digit, 21 combinations with 2 digits, 35 combinations with 3 digits, 35 combinations with 4 digits, 21 combinations with 5 digits, 7 combinations with 6 digits and 1 combinations with 7 digits. That makes a total of 2^7 - 1 = 127: too many for me to list. If digits can be repeated, there are infinitely many combinations.
There is only one combination. The order of the digits in combinations makes no difference. They are considered as being different if they are permutations, not combinations.
There are only 10 combinations. In each combination one of the 10 digits is left out.
654321-100000= 554321 combinations
Since a number can have infinitely many digits, there are infinitely many possible combinations.
Yuo can make only one combination of 30 digits using 30 digits.
Assuming you can repeat digits (like the number 1228 for example), there are 84 = 4096.If you can't repeat digits then it is equivalent to 8!/4! = 1680.
Since the order of the digits does not matter there are only five combinations: 1234, 1235, 1245, 1345 and 2345.
6 for 3-digits, 6 for 2-digits, 3 for 1-digits, and 15 for all of the combinations
With repeating digits, there are 33 = 27 possible combinations.Without repeating any digits, there are 6 combinations:357375537573735753
Oh, dude, you're hitting me with some math vibes here. So, if you have 6 digits to choose from to make a 4-digit combination, you can calculate that by using the formula for permutations: 6P4, which equals 360. So, like, you can make 360 different 4-digit combinations from those 6 digits. Math is wild, man.
0000-9999 (10x10x10x10 or 104) = 10,000 possible combinations allowing for repeated digits. If you are not able to repeat digits then it's 10 x 9 x 8 x 7 or 5,040 possible combinations without repeated digits.
You Can Create 999 Number combinations