Number of 7 digit combinations out of the 10 one-digit numbers = 120.
13579
It depends. If you can only use each number once, there are 720 combinations. If you can use numbers multiple times, then there are 1000 combinations, by using all numbers from 000 to 999.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
Since the order of the digits does not matter there are only five combinations: 1234, 1235, 1245, 1345 and 2345.
There are infinitely many numbers and so infinitely many possible combinations.
There are a huge number of combinations of 5 numbers when using the numbers 0 through 10. There are 10 to the 5th power combinations of these numbers.
9000
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
13579
36324
Using the combination fuction, chose three numbers from 45 numbers. The answer is 14,190.
There are 125970 combinations and I am not stupid enough to try and list them!
Using the formula n!/r!(n-r)! where n is the number of possible numbers and r is the number of numbers chosen, there are 13983816 combinations of six numbers between 1 and 49 inclusive.
The answer is 31C5 = 31!/[26!5!] = 169,911
It depends. If you can only use each number once, there are 720 combinations. If you can use numbers multiple times, then there are 1000 combinations, by using all numbers from 000 to 999.
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