First you need to find you first number. As there are five numbers, the first number can be any of the five. So you have five combinations (5). Next you take your second number, as you've already used one you can only choose one of four numbers (5 x 4). You third number, you can only choose one of three numbers (5 x 4 x 3), you fourth, one of two (5 x 4 x 3 x 2) and finally you are left with one number, so you only have one choice.
So we have a combination of 5 x 4 x 3 x 2 x 1 (or 5!) to find the number of different 5 number combinations you can make with 1, 2, 3, 4 and 5.
Answer: 120.
There are infinitely many numbers and so infinitely many possible combinations.
The number of combinations - not to be confused with the number of permutations - is 2*21 = 42.
To find the number of 3-digit combinations that can be made from the digits 1, 2, 3, 4, and 5, we consider that each digit can be used only once in each combination. The number of combinations is calculated using the formula for combinations: ( \binom{n}{r} ), where ( n ) is the total number of items to choose from, and ( r ) is the number of items to choose. Here, ( n = 5 ) and ( r = 3 ), so the number of combinations is ( \binom{5}{3} = 10 ).
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
If the order of the numbers are important, then this is a simple combination problem. There are 10 possible numbers to choose from for the first number. Then there are 9 options for the second number. Then there are 8 options for the third, and so on. Thus, the number of possible combinations can be calculated as 10x9x8x7x6x5. This comes out at 151,200 possible combinations.
There are only five combinations: 1234, 1235, 1245, 1345 and 2345.
There are: 12345C3 = 3.134847985*1011
Just 1.
There are 126 different 5 digit combinations. Note that the combination 12345 is the same as the combination 45312.
Since a number can have infinitely many digits, there are infinitely many possible combinations.
35
There are infinitely many numbers and so infinitely many possible combinations.
2^n possible combinations
If repeats are allowed than an infinite number of combinations is possible.
There are countless possible liquid combinations, depending on the types of liquids you are considering (water, juice, alcohol, etc.) and how many you want to mix together. The number of combinations would be exponential, as each additional liquid increases the number of possible combinations exponentially.
61
The number of combinations - not to be confused with the number of permutations - is 2*21 = 42.