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When creating a 6-number combination using digits from 0 to 9, where each digit can be repeated, there are 10 possible choices for each of the 6 positions. Therefore, the total number of combinations is calculated as (10^6), which equals 1,000,000.

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2mo ago

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How many 4 digit number combination are there using 1 3 5 7 and you can use each number more than once?

16 times


What are the 100000 number combinations you can make using 0 - 9?

The question is incorrect since there are 210 - 1 possible combinations. The digit 0 can be in the combination or out. That gives 2 ways. With each, the digit 1 can be in the combination or out - 2*2 = 22 ways. With each, the digit 2 can be in the combination or out = 23 ways. With each, the digit 3 can be in the combination or out = 24 ways. etc. So 210 ways in all except that one of them is the null combination. Now 210 = 1024 so there are only 1023 combinations. If, instead, you allow the digits to be used many times, there is no limit to the number of combinations.


How many 6 digit combinations of 102478 using each number once?

Only 1. In a combination, the order of the numbers does not matter. So 102478 is the same combination as 104782 or 407812 etc.


How many variations on a 9 digit number?

A 9-digit number can range from 000000000 to 999999999, which gives a total of 1,000,000,000 (or 10^9) possible variations. Each digit can be any number from 0 to 9, resulting in 10 choices for each of the 9 digits. Therefore, there are 10^9 variations of a 9-digit number.


How many combinations are there in a seven digit phone number?

There is only one combination. There are many permutations, though.


How many combinations are in a 5 digit number where all digits are distinct and nonzero?

There are 126 different 5 digit combinations. Note that the combination 12345 is the same as the combination 45312.


A combination lock on a suitcase has 5 wheels each labeled with digits 1 to 8 How many 5 digit combination lock codes are possible if no digit can be repeated?

6,720 combinations.


For her bicycle Lisa has a chain and a combination lock that has a 4-digit combination where each digit can range from 0 - 9 If adjacent digits must be different how many possible combinations can?

10x9x9x9


How many combinations of three digits can be made using each digit only once in each combination?

You have a three digit number that can only use each digit once in combination. Therefore, a number like 456 is acceptable, but 455 or 101 or 222 is not acceptable. I think you can solve the problem in the following manner. There are 10 possible digits (0-9) that can be used in the first number. For the second number there are only 9 possible since you cannot repeat one of the first. For the third number there are only 8 possible since again you cannot repeat any of the first two. You multiply the possibilities for each digit to get our answer. 10 * 9 * 8 = 720 There are 720 possible combinations.


How many 3 digit numbers can be formed from 3769 if each digit is used only once?

Choose from 4 for the first number, 3 for the second number, and 2 for the third number. Therefore there are 4*3*2 = 24 three digit numbers can be formed from 3769 if each digit is used only once.


How many five digit numbers can be formed using the numbers 1-60 only using each number once in each combination?

61


How many combinations are there for a 8 digit number 1-8?

Using the eight digits, 1 - 8 ,-- There are 40,320 eight-digit permutations.-- There is 1 eight-digit combination.