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How many 4 digit number combination are there using 1 3 5 7 and you can use each number more than once?
16 times
What are the 100000 number combinations you can make using 0 - 9?
The question is incorrect since there are 210 - 1 possible combinations. The digit 0 can be in the combination or out. That gives 2 ways. With each, the digit 1 can be in the combination or out - 2*2 = 22 ways. With each, the digit 2 can be in the combination or out = 23 ways. With each, the digit 3 can be in the combination or out = 24 ways. etc. So 210 ways in all except that one of them is the null combination. Now 210 = 1024 so there are only 1023 combinations. If, instead, you allow the digits to be used many times, there is no limit to the number of combinations.
How many 6 digit combinations of 102478 using each number once?
Only 1. In a combination, the order of the numbers does not matter. So 102478 is the same combination as 104782 or 407812 etc.
A combination lock on a suitcase has 5 wheels each labeled with digits 1 to 8 How many 5 digit combination lock codes are possible if no digit can be repeated?
6,720 combinations.
For her bicycle Lisa has a chain and a combination lock that has a 4-digit combination where each digit can range from 0 - 9 If adjacent digits must be different how many possible combinations can?
10x9x9x9
How many combinations are there in a seven digit phone number?
There is only one combination. There are many permutations, though.
How many combinations are in a 5 digit number where all digits are distinct and nonzero?
There are 126 different 5 digit combinations. Note that the combination 12345 is the same as the combination 45312.
How many combinations of three digits can be made using each digit only once in each combination?
You have a three digit number that can only use each digit once in combination. Therefore, a number like 456 is acceptable, but 455 or 101 or 222 is not acceptable. I think you can solve the problem in the following manner. There are 10 possible digits (0-9) that can be used in the first number. For the second number there are only 9 possible since you cannot repeat one of the first. For the third number there are only 8 possible since again you cannot repeat any of the first two. You multiply the possibilities for each digit to get our answer. 10 * 9 * 8 = 720 There are 720 possible combinations.
How many five digit numbers can be formed using the numbers 1-60 only using each number once in each combination?
61
How many combinations are there for a 8 digit number 1-8?
Using the eight digits, 1 - 8 ,-- There are 40,320 eight-digit permutations.-- There is 1 eight-digit combination.
How many 3 digit numbers can be formed from 3769 if each digit is used only once?
Choose from 4 for the first number, 3 for the second number, and 2 for the third number. Therefore there are 4*3*2 = 24 three digit numbers can be formed from 3769 if each digit is used only once.
How many 3 digit numbers have a first digit which is triple the final digit?
30.The first digit can be one of three digits {3, 6, 9} corresponding to the last digit being {1, 2, 3}, and for each of those three digits, the middle digit can be one of ten digits {0 - 9}, making 3 x 10 = 30 such numbers.It is assumed that a 3 digit number is a number in the range 100-999, excluding numbers starting with a leading zero, eg 090 is not considered a 3 digit number (though it would be a valid 3-digit number for a combination lock with 3 digits).
How many 4 digit numbers have 6 as their second digit?
There are 9 digits that can be the first digit (1-9); for each of these there is 1 digit that can be the second digit (6); for each of these there are 10 digits that can be the third digit (0-9); for each of these there are 10 digits that can be the fourth digit (0-9). → number of numbers is 9 × 1 × 10 × 10 = 900 such numbers.
How many different 9 digit combination can be made using numbers zero through nine?
Just think of how many possibilities you have for each digit. 10x9x8x7x6x5x4x3x2 or 10 factorial is 3 628 800.
How many different four digit combinations are there of the numbers zero through nine without using the same number twice in each combination?
The first digit can be any one of the ten symbols, 0 thru 9. For each of those . . .The second digit can be any one of the 9 that weren't used in the first place. For each of those . . .The third digit can be any one of the 8 that you haven't used yet. For each of those . . .The fourth digit can be any one of the 7 that haven't been used yet.Total number of possible arrangements = (10 x 9 x 8 x 7) = 5,040
How many decimal places in kg?
A decimal number is simply a way of representing a number in such a way that the place value of each digit is ten times that of the digit to its right. It is independent of a measurement unit.
How many combination codes is there using 4 5 6 7?
Oh, dude, let me break it down for you. So, if you have 4 options for the first digit, 5 for the second, 6 for the third, and 7 for the fourth, you just multiply those numbers together. So, 4 x 5 x 6 x 7 equals 840 possible combination codes. Easy peasy, right?
