When creating a 6-number combination using digits from 0 to 9, where each digit can be repeated, there are 10 possible choices for each of the 6 positions. Therefore, the total number of combinations is calculated as (10^6), which equals 1,000,000.
16 times
The question is incorrect since there are 210 - 1 possible combinations. The digit 0 can be in the combination or out. That gives 2 ways. With each, the digit 1 can be in the combination or out - 2*2 = 22 ways. With each, the digit 2 can be in the combination or out = 23 ways. With each, the digit 3 can be in the combination or out = 24 ways. etc. So 210 ways in all except that one of them is the null combination. Now 210 = 1024 so there are only 1023 combinations. If, instead, you allow the digits to be used many times, there is no limit to the number of combinations.
Only 1. In a combination, the order of the numbers does not matter. So 102478 is the same combination as 104782 or 407812 etc.
A 9-digit number can range from 000000000 to 999999999, which gives a total of 1,000,000,000 (or 10^9) possible variations. Each digit can be any number from 0 to 9, resulting in 10 choices for each of the 9 digits. Therefore, there are 10^9 variations of a 9-digit number.
6,720 combinations.
16 times
The question is incorrect since there are 210 - 1 possible combinations. The digit 0 can be in the combination or out. That gives 2 ways. With each, the digit 1 can be in the combination or out - 2*2 = 22 ways. With each, the digit 2 can be in the combination or out = 23 ways. With each, the digit 3 can be in the combination or out = 24 ways. etc. So 210 ways in all except that one of them is the null combination. Now 210 = 1024 so there are only 1023 combinations. If, instead, you allow the digits to be used many times, there is no limit to the number of combinations.
Only 1. In a combination, the order of the numbers does not matter. So 102478 is the same combination as 104782 or 407812 etc.
A 9-digit number can range from 000000000 to 999999999, which gives a total of 1,000,000,000 (or 10^9) possible variations. Each digit can be any number from 0 to 9, resulting in 10 choices for each of the 9 digits. Therefore, there are 10^9 variations of a 9-digit number.
There is only one combination. There are many permutations, though.
There are 126 different 5 digit combinations. Note that the combination 12345 is the same as the combination 45312.
6,720 combinations.
10x9x9x9
Choose from 4 for the first number, 3 for the second number, and 2 for the third number. Therefore there are 4*3*2 = 24 three digit numbers can be formed from 3769 if each digit is used only once.
You have a three digit number that can only use each digit once in combination. Therefore, a number like 456 is acceptable, but 455 or 101 or 222 is not acceptable. I think you can solve the problem in the following manner. There are 10 possible digits (0-9) that can be used in the first number. For the second number there are only 9 possible since you cannot repeat one of the first. For the third number there are only 8 possible since again you cannot repeat any of the first two. You multiply the possibilities for each digit to get our answer. 10 * 9 * 8 = 720 There are 720 possible combinations.
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Using the eight digits, 1 - 8 ,-- There are 40,320 eight-digit permutations.-- There is 1 eight-digit combination.