There are twelve possible solutions using the rule you stated.
10,000 combinations.
There is only 1 combination.
There are 360 of them.
Oh, what a lovely question! Let's paint a happy little picture here. To find the number of 6-digit combinations using 20 numbers, we can use a simple formula: 20P6, which stands for 20 permutations taken 6 at a time. This gives us 387,600 unique combinations to explore and create beautiful patterns with. Just imagine all the possibilities waiting to be discovered!
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
the answer is = first 2-digit number by using 48= 28,82 and in 3 digit is=282,228,822,822
There are twelve possible solutions using the rule you stated.
10,000 combinations.
To calculate the number of different 4-digit combinations that can be made using numbers 0 through 9, we use the concept of permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the number of options for each digit (10 in this case) and r is the number of digits (4 in this case). Therefore, the number of different 4-digit combinations that can be made using numbers 0 through 9 is 10^4, which equals 10,000 combinations.
Using the eight digits, 1 - 8 ,-- There are 40,320 eight-digit permutations.-- There is 1 eight-digit combination.
There are 840 4-digit combinations without repeating any digit in the combinations.
There is only 1 combination.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
If the digits can repeat, then there are 256 possible combinations. If they can't repeat, then there are 24 possibilities.
There are 5,040 combinations.
216