To find the number of 6-number combinations from a set of 138 numbers, you can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). For this case, ( n = 138 ) and ( k = 6 ), so it would be ( C(138, 6) = \frac{138!}{6!(138-6)!} ). Calculating this gives you a total of 4,182,400 combinations.
55C6 = 28,989,675
It is: 55C6 = 28,989,675
55C6 = 28,989,675
6 of them.
654321-100000= 554321 combinations
There are 8,592,039,666 combinations of 6 numbers out of 138 numbers, like the numbers from 1 to 138.
252 combinations, :)
There are 6C3 = 20 such combinations.
The number of combinations of 6 letters is 6! or 720.
Number of combinations = 45C6 = 45!/6!(45-6)! = 8,145,060
12,108,327
There are 8145060 combinations.
138 is divisible by 6. Any number is divisible by 6 if it is an even number that also is divisible by 3.
Any multiple of 138
just intrested in the number combinations * * * * * Number of combinations = 56C6 = 56*55*54*53*52*51/(6*5*4*3*2*1) = 32,468,436
It is: 55C6 = 28,989,675
55C6 = 28,989,675