8*7*6*5*4*3*2
8P7
=40,320
1. If you are really asking for combinations, in other words, if the order of the numbers chosen doesn't matter :
If each number can be selected only once, this is the number of choices of 7 from 8 _without replacement_:
8 choose 7 = 8
If each number can be selected more than once, this is the number of choice of 7 from 8 _with replacement_:
( 8 + 7 - 1 ) choose 7 = 3432
2. If the order of the numbers chosen matters as well as the combinations :
If each number can be selected only once, then there are 8 choices for the 1st number, 7 for the next, 6 for the one after that, and so on, or 8*7*6*5*4*3*2, as in the first answer.
However, if each number can be selected more than once, then there are 8 choices for the 1st number, (still) 8 choices for the next, 8 choices for the one after that, and so on, or 8*8*8*8*8*8*8 = 2097152.
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The number of combinations of six numbers that can be made from seven numbers will depend on if you can repeat numbers. In all there are over 2,000 different numbers that can be made.
9!/5! or 3024
8C6 = 28
None. You do not have enough numbers to make even one combination.
2 to the 7th power = 128 * * * * * No. That is the total number of combinations, consisting of any number of elements. The number of 2 number combinations is 7*6/2 = 21