Q: How many Pythagorean triples did Babylonians find?

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Since there are an infinite amount of whole numbers to make Pythagorean triples, there would be an infinite amount of Pythagorean triples to make.

Unlimited but the most common are 3,4,5; 5,12,13; and 6,8,10.

infinite............

There are many answers to the question provided by the Pythagorean Triples or sides of the integer right triangles where a, b, and c are integers and a2 + b2 = c2 Some examples are 3, 4, 5 ( 25 - 16 = 9) 6, 8, 10 (100 - 64 = 36) etc. See Pythagorean Triples for others.

a2 + b2 = c2

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Since there are an infinite amount of whole numbers to make Pythagorean triples, there would be an infinite amount of Pythagorean triples to make.

There are infinitely many Pythagorean triples. To find a Pythagorean triple take two positive integers x, y with x > y. A Pythagorean triple is of the form x2 - y2, 2xy, x2 + y2.

Unlimited but the most common are 3,4,5; 5,12,13; and 6,8,10.

infinite............

You could use the Pythagorean Theorem and many triangles You could use the Pythagorean Theorem and many triangles

There are many answers to the question provided by the Pythagorean Triples or sides of the integer right triangles where a, b, and c are integers and a2 + b2 = c2 Some examples are 3, 4, 5 ( 25 - 16 = 9) 6, 8, 10 (100 - 64 = 36) etc. See Pythagorean Triples for others.

Because many of them were descended from Babylonians, and they made Babylon their capital.

The babylonians divided the day into 24 hours, each hour into 60 minutes, each minute into 60 seconds.

There are many different methods: the simpler methods will generate lots of triplets but not all. Comprehensive generators tend to be very complex. So here is a simple one: Euclid's formula Take any two positive integers x and y and suppose x > y. Then A = x2 - y2 B = 2xy C = x2 + y2 form a Pythagorean triplet.

Sumerian

The Babylonians believed in many gods and priests. They believed that if they disobeyed the gods they would be severally punished!! Hope this helps!!

a2 + b2 = c2