There are many different methods: the simpler methods will generate lots of triplets but not all. Comprehensive generators tend to be very complex.
So here is a simple one: Euclid's formula
Take any two positive integers x and y and suppose x > y. Then
A = x2 - y2
B = 2xy
C = x2 + y2
form a Pythagorean triplet.
Yes
They are Pythagorean triples
They are Pythagorean triples
Euclid's Formula is a method of generating Pythagorean Triples. A Pythagorean Triple is a set of three positive integers (whole numbers), which satisfy the equation a2 + b2 = c2. The smallest Pythagorean Triple is 3, 4, 5. Euclid's Formula says this: If you choose two positive integers m and n, with m < n, then the three numbers n2 - m2, 2mn and n2 + m2 form a Pythagorean Triple. For example, if m = 5 and n = 7, n2 - m2 = 49 - 25 = 24, 2mn = 70, and n2 + m2 = 49 + 25 = 74. 24, 70, 74 is a PT, because 242 + 702 = 742. That's how to use Euclid's Formula. If the question means why does it work, then: (n2 - m2)2 + (2mn)2 = (n4 + m4 - 2n2m2) + (4m2n2) = n4 + m4 + 2n2m2, which is the same thing as (n2 + m2)2 . Two things to note are: The Formula does not generate all possible Triples, and it will generate Primitive Triples (ones with no common factor), only if m and n have no common factor, (except 1).
x=4 y=1
3,4,5 1,2,3 these are sets of pythagorean triples
Since there are an infinite amount of whole numbers to make Pythagorean triples, there would be an infinite amount of Pythagorean triples to make.
No, the multiple of any random triple is not a Pythagorean triple.
No.
Pythagorean triples: 3, 4 and 5 or 5, 12 and 13 are two of them
You seem to have squashed the numbers together but 4, 3 and 5 make up a Pythagorean triple.
Chinese and babylonians
Yes
Pythagorean Triples
Beacause it works
no one knows.
There are infinitely many Pythagorean triples. To find a Pythagorean triple take two positive integers x, y with x > y. A Pythagorean triple is of the form x2 - y2, 2xy, x2 + y2.