28-bits
the Bit depth
The largest positive value that can be stored in 20 bits is calculated using the formula for the maximum value of an unsigned binary number, which is (2^n - 1), where (n) is the number of bits. For 20 bits, this is (2^{20} - 1 = 1,048,576 - 1 = 1,048,575). Therefore, the largest positive value that can be stored in 20 bits is 1,048,575.
To represent an eight-digit decimal number in Binary-Coded Decimal (BCD), each decimal digit is encoded using 4 bits. Since there are 8 digits in the number, the total number of bits required is 8 digits × 4 bits/digit = 32 bits. Therefore, 32 bits are needed to represent an eight-digit decimal number in BCD.
The number of digits in a binary number, also known as its bits, depends on its value. For a binary number representing a non-negative integer ( n ), the number of bits required can be calculated using the formula ( \lfloor \log_2(n) \rfloor + 1 ). For example, the binary representation of the decimal number 5 is ( 101 ), which has 3 bits. The number of bits increases as the value of ( n ) increases.
The largest binary number that can be expressed with 16 bits is 1111111111111111, which is equivalent to 65,535 in decimal. This number uses all 16 bits set to 1. In general, for an n-bit binary number, the maximum value is (2^n - 1). Thus, for 16 bits, it is (2^{16} - 1 = 65,535).
Eight.
The Word Size.
To store the hexadecimal number FF, we need to convert it to binary first. FF in hexadecimal is equivalent to 1111 1111 in binary, which requires 8 bits to represent. Each hexadecimal digit corresponds to 4 bits in binary, so two hexadecimal digits (FF) require 8 bits to store.
the Bit depth
log(number of generations) / log(2) Round the answer up.
255 is the largest decimal number. 1 byte (8 bits) can store 256 *values* (0-255).
The largest positive value that can be stored in 20 bits is calculated using the formula for the maximum value of an unsigned binary number, which is (2^n - 1), where (n) is the number of bits. For 20 bits, this is (2^{20} - 1 = 1,048,576 - 1 = 1,048,575). Therefore, the largest positive value that can be stored in 20 bits is 1,048,575.
40 bits or 5 byrtes
The MIN (Mobile Identification Number) is a number that uniquely identifies a mobile telephone subscriber. MINs are 34-bits in length. The first 10 bits are sometimes known as MIN2, while the last 24 bits are referred to as MIN1. Together they are simply known as the MIN. In the United States, the MIN is derived from the 10 digital decimal telephone number assigned to the handset. For the telephone number (303)866-1010, the area code ("303″) becomes the 10 bit MIN2 and the local portion of the telephone number ("866-1010″) becomes the 24 bit MIN1. Internationally, MINs are calculated in a different fashion. The three digit mobile carrier identification number becomes MIN2 and the local portion of the telephone number becomes MIN1. IFAST, the International Forum on ANSI-41 Standards Technology, assigns the mobile carrier identification numbers. A MIN in this format is known as an IRM (International Roaming MIN). Unlike the IMEI, the MIN is not an attribute of the physical phone. The MIN is stored in a database that the cellular provider manages and can be changed at any time.
In ASCII code, each letter, number or punctuation mark takes one byte, or 8 bits. That gives you 256 discrete combinations. Two letters take 2 bytes, or 16 bits.
A small number filp flop is used to store the memory in bits(0's and 1's)
1 byte = 8 bits.