heat will flow from the iron to the water until both are the same temperature
That's going to depend on the temperature of the water before you heat it, and on how hot you want it to be when you're done.
You would need to remove approximately 1200 BTUs of heat to convert a gallon of water to ice. There are 8.34 lb in a gallon of water, which converting to lb-moles is 0.463. The latent heat of crystallization for water is -2583.4 BTU/lb-mole. Multiplying the two together and you get -1197 BTUs, which means you need to remove that amount of heat to convert the gallon of water to ice.
"Watt" is a rate of moving energy. The more watts you use, the faster the waterwill heat up. The fewer watts you use, the slower it will heat. If you can affordthe time to wait, then any amount of power will do the job, no matter how small.
answer: 7680 btu 1 gallon= 8 lb 130F-50F=80F 12G*8LB*80F=7680 BTU
The amount of natural gas therms required to boil water depends on the volume of water and the efficiency of the heating system. On average, it takes about 0.12 therms to heat a gallon of water, but this can vary based on factors like starting water temperature and insulation of the heating system.
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The amount of propane needed to heat a 50 gallon water heater from 75 degrees to 105 degrees would depend on factors such as the efficiency of the water heater, the starting temperature of the water, and the ambient temperature. It is difficult to provide an exact amount without this information.
no
heat will flow from the iron to the water until both are the same temperature
That's going to depend on the temperature of the water before you heat it, and on how hot you want it to be when you're done.
You would need to remove approximately 1200 BTUs of heat to convert a gallon of water to ice. There are 8.34 lb in a gallon of water, which converting to lb-moles is 0.463. The latent heat of crystallization for water is -2583.4 BTU/lb-mole. Multiplying the two together and you get -1197 BTUs, which means you need to remove that amount of heat to convert the gallon of water to ice.
That depends on the starting temperature of the cold water and the starting temperature of the hot water.
depends on the wattage of the elements along with the temp of the cold water but i would guess an hour or two
To heat a 390 gallon tank of water from 60°F to 248°F, you would need approximately 1,251,600 BTUs. This calculation takes into account the specific heat capacity of water (1 BTU/lb°F) and the weight of water (8.34 lbs/gallon).
No. Heat is one of many forms of energy, and is measured in units of energy ... joules, calories, watt-seconds, BTU, foot-pounds, etc. "Degrees" describe the temperature of an object or a sample of a substance. That's a measure of how "full of heat" it is. One joule of heat will fill an ounce of water higher than the same joule will fill a gallon of water. So after absorbing the same amount of heat, the temperature of the ounce is higher than the gallon's temperature.
The heat content of a gallon of water at a certain temperature can be calculated using the specific heat capacity of water (1 calorie/gram °C). For example, to calculate the heat content of a gallon of water at 20°C, you would need to know the mass of the water and apply the formula: heat content = mass of water x specific heat capacity x temperature change.