100=2*2*5*5 so only 1 combination of 3 nos. r der
Just the one. The order of the numbers does not matter in a combination so that 123456 is the same combination as 245136.
120 WRONG! That is the number of PERMUTATIONS. In the case of combinations, the order of the numbers does not matter, so there is only 1 5-number combination from 5 numbers.
This question does not make sense since a combination is independent of the order of its elements. That is, the combinations 1245 and 5142 are the same. Consequently, there can be no "last " numbers in a combination.
It depends on how many numbers are in each combination. If there are 5 numbers in each combination, then you have 575,757 possibilities. If there are 2 in each combination, there you have 741 possibilities. If there's only 1 number in each combination, then there are only 39 possibilities.
5*4*3*2*1 = 120 combinations. * * * * * No. The previous answerer has confused permutations and combinations. There are only 25 = 32 combinations including the null combinations. There is 1 combination of all 5 numbers There are 5 combinations of 4 numbers out of 5 There are 10 combinations of 3 numbers out of 5 There are 10 combinations of 2 numbers out of 5 There are 5 combinations of 1 numbers out of 5 There is 1 combination of no 5 numbers 32 in all, or 31 if you want to disallow the null combination.
100=2*2*5*5 so only 1 combination of 3 nos. r der
Number of combinations = 59*58*57*56*55/(5*4*3*2*1) = 5006386.
Just the one. The order of the numbers does not matter in a combination so that 123456 is the same combination as 245136.
120 WRONG! That is the number of PERMUTATIONS. In the case of combinations, the order of the numbers does not matter, so there is only 1 5-number combination from 5 numbers.
This question does not make sense since a combination is independent of the order of its elements. That is, the combinations 1245 and 5142 are the same. Consequently, there can be no "last " numbers in a combination.
It depends on how many numbers are in each combination. If there are 5 numbers in each combination, then you have 575,757 possibilities. If there are 2 in each combination, there you have 741 possibilities. If there's only 1 number in each combination, then there are only 39 possibilities.
about... 25 just take 5 numbers times 5 numbers
6 over 3, or 6 combination 3, is calculated as (6 x 5 x 4) / (1 x 2 x 3).
Using the combination C(4,3) I got the answer 24. Its either a combination or a permutation.
None. 3 digit numbers are not divisible by 19 digit numbers.
There are 5*5*5 = 125 such numbers.