3!*3!=36For example, if you want to use the alphabets a,b,c and three digits 1,2,3 you can make the following 36 different passwords (3 letters followed by 3 digits)abc123abc132abc231abc213abc312abc321acb123acb132acb231acb213acb312acb321bca123bca132bca231bca213bca312bca321bac123bac132bac231bac213bac312bac321cab123cab132cab231cab213cab312cab321cba123cba132cab231cab213cab312cab321
11,232,000
Allowing repetitions, there are 9 combinations. Without repeated digits, there is only one combination of 3 digits from 3.
You Can Create 999 Number combinations
Using the combination C(4,3) I got the answer 24. Its either a combination or a permutation.
3 letters
3!*3!=36For example, if you want to use the alphabets a,b,c and three digits 1,2,3 you can make the following 36 different passwords (3 letters followed by 3 digits)abc123abc132abc231abc213abc312abc321acb123acb132acb231acb213acb312acb321bca123bca132bca231bca213bca312bca321bac123bac132bac231bac213bac312bac321cab123cab132cab231cab213cab312cab321cba123cba132cab231cab213cab312cab321
This depends on if you want repeats or not (or the state you are in) with repeats it is: 26x26x26x10x10= 1,757,600 without repeats it is: 26x25x24x10x9=1,560,000
11,232,000
Allowing repetitions, there are 9 combinations. Without repeated digits, there is only one combination of 3 digits from 3.
2600
You Can Create 999 Number combinations
There are 26 different letters that can be chosen for each letter. There are 10 different numbers that can be chosen for each number. Since each of the numbers/digits that can be chosen for each of the six "spots" are independent events, we can multiply these combinations using the multiplicative rule of probability.combinations = (# of different digits) * (# of different digits) * (# of different digits) * (# of different letters) * (# of different letters) * (# of different letters) = 10 * 10 * 10 * 26 * 26 * 26 = 103 * 263 = 1000 * 17576 = 17,576,000 different combinations.
Using the combination C(4,3) I got the answer 24. Its either a combination or a permutation.
The question is ambiguous. It is in complete.
The answer is 26*26*26*10*10*10 = 17,576,000
3 decimal digits without repeats can form (10 x 9 x 8) = 720 distinct displays.For each of these . . .3 letters without repeats can form (26 x 25 x 24) = 15,600 distinct displays.Combine them on one plate, and there are (720) x (15,600) = 11,232,000 distinct displays available.