To determine the number of combinations of a set of 24 items, you need to specify how many items you want to choose from that set. The formula for combinations is given by ( C(n, r) = \frac{n!}{r!(n-r)!} ), where ( n ) is the total number of items, and ( r ) is the number of items to choose. For example, if you want to choose 2 items from 24, the number of combinations would be ( C(24, 2) = \frac{24!}{2!(24-2)!} = 276 ).
24
24
4!=4x3x2x1=24
4! = 4*3*2*1 = 24 of them.
The letters M, A, T, and H can be arranged in different combinations by calculating the factorial of the number of letters. Since there are 4 unique letters, the total number of combinations is 4! (4 factorial), which equals 24. Therefore, 24 different combinations of the letters M, A, T, and H can be formed.
There are 24C12 = 24!/[12!*12!] = 2,704,156 combinations.
There are 24C12 = 24*23*...*13/(12*11*...*1) = 2,704,156 combinations.
24
Three combinations: 23, 24 and 34
24C7 = 24!/((24-7)!7!) = 346,104.
24
24
24
4*3*2*1 = 24 different combinations.
4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.
24 of them.
4!=4x3x2x1=24