To find the number of combinations of 3 out of 18, you can use the combination formula: ( C(n, r) = \frac{n!}{r!(n-r)!} ). Here, ( n = 18 ) and ( r = 3 ). Plugging in the values, we get ( C(18, 3) = \frac{18!}{3!(18-3)!} = \frac{18 \times 17 \times 16}{3 \times 2 \times 1} = 816 ). Therefore, there are 816 combinations of 3 out of 18.
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233 = 18 combinations.
There are 18C4 = 18!/[18-4)!4!] = 18*17*16*15/(4*3*2*1) = 3060 combinations.
There are 18 permutations or 5 combinations. And it is one die, many dice. There is no such word as dices or diceses.
3 items each in 3 categories gives 3*3*3 = 27 possible combinations.
11*3*3 = 99 combinations.