all numbers have to be different 720 360 (6*5*4*3*2*1),
* * * * *
Wrong. Combinations do not have to be different. Those are permutations.
There are only 6C4 = 6*5/(2*1) = 15 combinations.
There is 1 combination of all ten numbers, 10 combinations of one number and of nine numbers, 45 combinations of two or eight numbers, 120 combinations of three or seven numbers, 210 combinations of four or six numbers and 252 combinations of five numbers. That is 1023 = 210 - 1 in total.
every number from 0000 to 9999
There are 360 of them.
There are 10,000 four number combinations in the numbers 0 through 9. * * * * * No, that is simply not true. The combination 1234 is the same as the combination 2134 and 2314 and 1423 etc. So, there are just 8*7*6*5/(4*3*2*1) = 70 combinations.
shut up guys
There is 1 combination of all ten numbers, 10 combinations of one number and of nine numbers, 45 combinations of two or eight numbers, 120 combinations of three or seven numbers, 210 combinations of four or six numbers and 252 combinations of five numbers. That is 1023 = 210 - 1 in total.
every number from 0000 to 9999
There are 360 of them.
There are 10,000 four number combinations in the numbers 0 through 9. * * * * * No, that is simply not true. The combination 1234 is the same as the combination 2134 and 2314 and 1423 etc. So, there are just 8*7*6*5/(4*3*2*1) = 70 combinations.
shut up guys
19
You can get only four combinations: They are: 11, 118, 119 and 1189. In a combination, the order of the digits does not matter.
This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.
How many numbers are there are in each combination ?If one, then 4 combinations.If two, then 6 combinations.If three, then 4 combinations.If four, then only 1 combination.
4!=4x3x2x1=24
How many place combinations in a four digit number and all have to go in different spot example: 1234, 4321, 2134 etc. numbers can't change and have to stay four numbers?The answer would be 36 different combinations. This is simply the counting principle and it's easy for anyone to learn.
10 000 * * * * * NO! That is the number of PERMUTATIONS, not COMBINATIONS. In a combination, the order does not matter so that 1234 is the same as 1432 or 3412 etc. Assuming the 4 numbers are different, the correct answer is 15 comprising 4 1-digit combinations, 6 2-digit combinations, 4 3-digit combinations and 1 4-digit combination. Another way to look at it is that the first number can be in a combination or not. With each of these possibilities, the second can be in or out - giving 2*2 = 4 ways so far. With each of these there are two options for the third giving 2*2*2 = 8 combinations so far and then the last number makes it 2*2*2*2 = 16. But one of these combinations contains none of the numbers - each one is not in. Leaving that one out gives the answer 15. In general, the number of combinations of any size, from n distinct objects is 2n and if you exclude the null combination, it is 2n - 1.