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If each number is different from all of the other numbers and the combinations are considered distinct unless they contain the same numbers in the same order, the answer is 25 X 24 X 23 X 22 X 21 = 6,375,600. If the combinations are distinct only if they do not contain the same numbers, irrespective of order, then the answer is (25 X 24 X 23 X 22 X 21)(5 x 4 x 3 x 2) = 53,130.
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How many different combinations of 5 numbers can you get from the numbers 1 -25 with no number repeated in a combination?
To calculate the number of different combinations of 5 numbers chosen from 1 to 25 without repetition, we can use the formula for combinations: nCr = n! / r!(n-r)!. In this case, n = 25 (total numbers) and r = 5 (numbers chosen). Therefore, the number of combinations is 25! / (5!(25-5)!) = 53,130 different combinations.
How many combinations are there in set of 5 for numbers 1 25?
If the numbers are all different, then 25C5 = 25*24*23*22*21/(5*4*3*2*1) = 53,130.
How many combinations of 5 different numbers if there are 5 numbers?
120
How many combinations of 5 are there in 0 to 10 numbers?
There are a huge number of combinations of 5 numbers when using the numbers 0 through 10. There are 10 to the 5th power combinations of these numbers.
How many combinations in sets of 5 using the numbers 1 thru 10?
There are 252 combinations.
How many combinations are there with 5 numbers?
5*4*3*2*1 = 120 combinations. * * * * * No. The previous answerer has confused permutations and combinations. There are only 25 = 32 combinations including the null combinations. There is 1 combination of all 5 numbers There are 5 combinations of 4 numbers out of 5 There are 10 combinations of 3 numbers out of 5 There are 10 combinations of 2 numbers out of 5 There are 5 combinations of 1 numbers out of 5 There is 1 combination of no 5 numbers 32 in all, or 31 if you want to disallow the null combination.
How many different combinations of 5 numbers can you get from the numbers 1 -25 with no number repeated in a combination?
To calculate the number of different combinations of 5 numbers chosen from 1 to 25 without repetition, we can use the formula for combinations: nCr = n! / r!(n-r)!. In this case, n = 25 (total numbers) and r = 5 (numbers chosen). Therefore, the number of combinations is 25! / (5!(25-5)!) = 53,130 different combinations.
How many combinations are there in set of 5 for numbers 1 25?
If the numbers are all different, then 25C5 = 25*24*23*22*21/(5*4*3*2*1) = 53,130.
How many combinations of 5 different numbers if there are 5 numbers?
120
How many combinations can you make with the numbers 2 3 6 7 and 8?
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
How many combinations of 5 are there in 0 to 10 numbers?
There are a huge number of combinations of 5 numbers when using the numbers 0 through 10. There are 10 to the 5th power combinations of these numbers.
How many combinations of 5 numbers are there in 31 numbers?
31C5 = 169911
What are all the multiplication combinations for 25?
If you have to stick with positive whole numbers, then there are only two: 1 x 25 and 5 x 5
How many combinations of 5 numbers are possible from 17 numbers?
There are: 17C5 = 6188
How many combinations in sets of 5 using the numbers 1 thru 10?
There are 252 combinations.
How many combinations can you get out of 40 numbers in groups of 6?
5
How many different combinations of 5 numbers 5 number combination?
120 WRONG! That is the number of PERMUTATIONS. In the case of combinations, the order of the numbers does not matter, so there is only 1 5-number combination from 5 numbers.
