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If each number is different from all of the other numbers and the combinations are considered distinct unless they contain the same numbers in the same order, the answer is 25 X 24 X 23 X 22 X 21 = 6,375,600. If the combinations are distinct only if they do not contain the same numbers, irrespective of order, then the answer is (25 X 24 X 23 X 22 X 21)(5 x 4 x 3 x 2) = 53,130.
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How many different combinations of 5 numbers can you get from the numbers 1 -25 with no number repeated in a combination?
To calculate the number of different combinations of 5 numbers chosen from 1 to 25 without repetition, we can use the formula for combinations: nCr = n! / r!(n-r)!. In this case, n = 25 (total numbers) and r = 5 (numbers chosen). Therefore, the number of combinations is 25! / (5!(25-5)!) = 53,130 different combinations.
How many combinations are there in set of 5 for numbers 1 25?
If the numbers are all different, then 25C5 = 25*24*23*22*21/(5*4*3*2*1) = 53,130.
How many combinations of 5 different numbers if there are 5 numbers?
120
How many combinations of 5 are there in 0 to 10 numbers?
There are a huge number of combinations of 5 numbers when using the numbers 0 through 10. There are 10 to the 5th power combinations of these numbers.
How many combinations in sets of 5 using the numbers 1 thru 10?
There are 252 combinations.
