Q: How many possible combinations of six numbers are possible from six numbers?

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7

Six combinations: 123, 132, 213, 231, 312, 321

6X6=36

If you mean how many different ways can you arrange six numbers, its 6! which is six factorial, I'm not just really happy about that. Thats because there are six options for the first of the numbers, 5 for the second (because one has been removed), 4 for the third and so on. And six factorial = 6 * 5 * 4 * 3 * 2 * 1 n! = 1 * 2 * 3 * ... * (n-2) * (n-1) * n * * * * * That is not correct. In a combination, the order of the numbers does not matter so that 123456 is the same as 135246 and so on. What matters is how many numbers the six are being selected from. If the six are being selected from n different numbers, the number of combinations is nC6 = n!/[6!(n-6)!] where n! is as defined above, and 0! = 1

46656

Related questions

If the numbers are allowed to repeat, then there are six to the fourth power possible combinations, or 1296. If they are not allowed to repeat then there are only 360 combinations.

figure it out then tell me :)

The number of combinations of six numbers that can be made from seven numbers will depend on if you can repeat numbers. In all there are over 2,000 different numbers that can be made.

Assuming that the six numbers are different, the answer is 15.

There are many different combinations of six numbers, but the sum of those numbers would have to be 24.

7

Using the formula n!/r!(n-r)! where n is the number of possible numbers and r is the number of numbers chosen, there are 13983816 combinations of six numbers between 1 and 49 inclusive.

There are 8C6 = 8*7/(2*1) = 28 combinations.

There are: 7C6 = 7

3!(factorial) or six

Six * * * * * No, that is the number of PERMUTATIONS (not combinations). With 3 numbers, the number of combinations, including the null combination, is 23 = 8. With the three numbers 1,2 and 3, these would be {None of them}, {1), {2), {3}, {1, 2}, {1, 3}, {2, 3}, {1, 2, 3}.

There are six possible combinations.