Oh, dude, a decagon has 10 sides, right? So, if you pick one vertex and want to draw diagonals, you can draw diagonals to all the other vertices except the adjacent ones, which are already sides. So, you can draw 7 diagonals from that one vertex. Math can be fun, like a puzzle... or a headache, depending on how you look at it.
In a decagon, which is a 10-sided polygon, there are 7 diagonals that can be drawn from one vertex. This can be calculated using the formula n(n-3)/2, where n represents the number of sides of the polygon. So for a decagon, there are 10(10-3)/2 = 7 diagonals that can be drawn from one vertex.
12-3 = 9
If you mean "How many diagonals can be drawn from one vertex of a figure with 16 sides", the formula is n-3, where "n" being the number of sides of the figure. So 16-3 = 13 diagonals that can be drawn from one vertex.
98
5 triangles are formed.
A vertex is the same as an angle. A decagon has 10.A vertex is the same as an angle. A decagon has 10.A vertex is the same as an angle. A decagon has 10.A vertex is the same as an angle. A decagon has 10.
If all of the diagonals are drawn from a vertex of an octagon, how many triangles are formed
There are 8
It is 18 diagonals
3
Three
Depends on the shape.
In a polygon with n sides, the number of diagonals that can be drawn from one vertex is given by the formula (n-3). Therefore, in a 35-sided polygon, you can draw (35-3) = 32 diagonals from one vertex.
n-3 from each vertex.
36
5
In a 54-sided polygon, 53 possible diagonals can be drawn from one vertex to another. These diagonals will not intersect. Therefore, the interior will be divided into 54 regions by the 53 diagonals plus the two sides of the original polygon that adjoin the vertex from which the diagonals are drawn.
12-3 = 9